Is it possible to see the interface of a loaded module in interactive OCaml? I have (unsuccessfully) tried searching for such a possibility, and online docs/sources are not what I am looking for.
The standard trick for this is to define a synonym for the module, which induces the toplevel to list the interface.
$ ocaml
OCaml version 4.00.1
# #load "str.cma";;
# module S = Str;;
module S :
sig
type regexp = Str.regexp
val regexp : string -> regexp
val regexp_case_fold : string -> regexp
val quote : string -> string
val regexp_string : string -> regexp
val regexp_string_case_fold : string -> regexp
val string_match : regexp -> string -> int -> bool
. . .
val first_chars : string -> int -> string
val last_chars : string -> int -> string
end
Update
(Note that this answer is from 2013. Recent revisions of OCaml provide a toplevel directive to show a module interface:
# #show_module Str;;
module Str :
sig
type regexp
val regexp : string -> regexp
. . .
val first_chars : string -> int -> string
val last_chars : string -> int -> string
end
So the semi-clever workaround is no longer required.
(There are many new directives. Type #help;;
at toplevel to get a list.)
Both utop and ocaml interpreters added the #show directive since a moment. It does exactly what you want, as in the following example :
│ Welcome to utop version 1.19.3 (using OCaml version 4.04.0) │
└──────────────────────────────────────────────────────────────┘
Type #utop_help for help about using utop.
─( 15:12:33 )─< command 0 >──────────────────────────────────────{ counter: 0 }─
utop # #show List;;
module List :
sig
val length : 'a list -> int
val cons : 'a -> 'a list -> 'a list
val hd : 'a list -> 'a
...
val fast_sort : ('a -> 'a -> int) -> 'a list -> 'a list
val sort_uniq : ('a -> 'a -> int) -> 'a list -> 'a list
val merge : ('a -> 'a -> int) -> 'a list -> 'a list -> 'a list
end
PS:i'm using 4.04 version but i know that it also works for 4.03.> and maybe before that too.
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