Is there a way to partition and reshape a 2D array to a 3D one. Like the following example:
Basically, I have a 4x4 matrix on the left and I want a 2x2x4 matrix in the way shown, so that I can apply numpy.mean on the 3rd axis. In reality the matrix I have is really huge, so that's why looping over the blocks is not an option.
Any help is greatly appreciated.
reshape() is an inbuilt function in python to reshape the array. We can reshape into any shape using reshape function. This function gives a new shape to the array.
Use numpy. array() to create a 3D NumPy array with specific values. Call numpy. array(object) with object as a list containing x nested lists, y nested lists inside each of the x nested lists, and z values inside each of the y nested lists to create a x -by- y -by- z 3D NumPy array.
For your example, you can use numpy.lib.stride_tricks.as_strided.
In [1]: A = np.arange(16).reshape(4, 4)
In [2]: A
Out[2]:
array([[ 0, 1, 2, 3],
[ 4, 5, 6, 7],
[ 8, 9, 10, 11],
[12, 13, 14, 15]])
In [3]: strides = A.itemsize * np.array([8, 2, 4, 1])
In [4]: x = p.lib.stride_tricks.as_strided(A, shape = (2, 2, 2, 2), strides = strides)
In [4]: x
Out[4]:
array([[[[ 0, 1],
[ 4, 5]],
[[ 2, 3],
[ 6, 7]]],
[[[ 4, 5],
[ 8, 9]],
[[ 6, 7],
[10, 11]]]])
In [5]: x.reshape(4, 2, 2)
Out[5]:
array([[[ 0, 1],
[ 4, 5]],
[[ 2, 3],
[ 6, 7]],
[[ 8, 9],
[12, 13]],
[[10, 11],
[14, 15]]])
The strides define offsets in bytes to use when traversing the array, and the as_strided
function enables you to build a new array with user-define strides.
However, I do not know how efficient it is and how well it will scale for your use.
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