I'm having trouble to create an array of random choices, where a choice is a tuple.
I get the error: a must be 1-dimensional
Here is an example:
choices = ((0,0,0),(255,255,255)) numpy.random.choice(choices,4)
Is there any other way to do this?
Expected result:
a numpy array consiting of 4 elements randomly picked from the choices tuple.
((0,0,0),(0,0,0),(255,255,255),(255,255,255))
Use random. choice(seq) which is inbuilt function in Random Module. It will return the randomly selected element. “seq” could be list, tuple or string but should not be empty.
The choice() method allows you to generate a random value based on an array of values. The choice() method takes an array as a parameter and randomly returns one of the values.
Python Random choice() Method The choice() method returns a randomly selected element from the specified sequence. The sequence can be a string, a range, a list, a tuple or any other kind of sequence.
Use choice
to choose the 1dim indices into the array, then index it.
In the example you provided, only the number of possible choices affects the nature of the choice, not the actual values (0, 255). Choosing indices is the 1dim problem choice
knows how to handle.
choices = numpy.array([[0,0,0],[255,255,255]]) idx = numpy.random.choice(len(choices),4) choices[idx]
Just adding this answer to provide a non-numpy
based answer:
choices = ((0,0,0),(255,255,255)) from random import choice print tuple(choice(choices) for _ in range(4))
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