I have 2 2D-arrays. I am trying to convolve along the axis 1. np.convolve
doesn't provide the axis
argument. The answer here, convolves 1 2D-array with a 1D array using np.apply_along_axis
. But it cannot be directly applied to my use case. The question here doesn't have an answer.
MWE is as follows.
import numpy as np
a = np.random.randint(0, 5, (2, 5))
"""
a=
array([[4, 2, 0, 4, 3],
[2, 2, 2, 3, 1]])
"""
b = np.random.randint(0, 5, (2, 2))
"""
b=
array([[4, 3],
[4, 0]])
"""
# What I want
c = np.convolve(a, b, axis=1) # axis is not supported as an argument
"""
c=
array([[16, 20, 6, 16, 24, 9],
[ 8, 8, 8, 12, 4, 0]])
"""
I know I can do it using np.fft.fft
, but it seems like an unnecessary step to get a simple thing done. Is there a simple way to do this? Thanks.
The convolution of 2 arrays is defined as C[i + j] = ∑(a[i] * b[j]) for every i and j.
An array in numpy is a signal. The convolution of two signals is defined as the integral of the first signal, reversed, sweeping over ("convolved onto") the second signal and multiplied (with the scalar product) at each position of overlapping vectors.
An array needs to explicitly import the array module for declaration. A 2D array is simply an array of arrays. The numpy. array_split() method in Python is used to split a 2D array into multiple sub-arrays of equal size.
Why not just do a list comprehension with zip
?
>>> np.array([np.convolve(x, y) for x, y in zip(a, b)])
array([[16, 20, 6, 16, 24, 9],
[ 8, 8, 8, 12, 4, 0]])
>>>
Or with scipy.signal.convolve2d
:
>>> from scipy.signal import convolve2d
>>> convolve2d(a, b)[[0, 2]]
array([[16, 20, 6, 16, 24, 9],
[ 8, 8, 8, 12, 4, 0]])
>>>
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