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numpy array using python's long type

I am trying to create a numpy array with type long (that is, Python's long, not numpy's long = int64).

If I do:

m = np.eye(6, dtype=long)
print(m.dtype)

This outputs int64; i.e., they are not Python longs.

Is there any way to create a numpy array with each element being of type long? Or is this some fixed-width versus non-fixed-width problem that numpy doesn't support? If so, is there any library (preferably with a nice C API like numpy's) that can do this?

like image 766
user2211937 Avatar asked Mar 26 '14 14:03

user2211937


1 Answers

Python's long integer type is not a native numpy type, so you will have to use the object data type. The elements of an numpy array with object type can be any python objects.

For example,

In [1]: x = np.array([1L, 2L, 3L], dtype=object)

In [2]: x
Out[2]: array([1L, 2L, 3L], dtype=object)

In [3]: x[0]
Out[3]: 1L

In [4]: type(x[0])
Out[4]: long

Whether or not this is useful for you depends on what you want to do with the array of longs.

like image 136
Warren Weckesser Avatar answered Sep 23 '22 07:09

Warren Weckesser