I am trying to create a numpy array with type long
(that is, Python's long
, not numpy's long = int64
).
If I do:
m = np.eye(6, dtype=long)
print(m.dtype)
This outputs int64
; i.e., they are not Python long
s.
Is there any way to create a numpy array with each element being of type long
? Or is this some fixed-width versus non-fixed-width problem that numpy doesn't support? If so, is there any library (preferably with a nice C API like numpy's) that can do this?
Python's long integer type is not a native numpy type, so you will have to
use the object
data type. The elements of an numpy array with object
type can be any python objects.
For example,
In [1]: x = np.array([1L, 2L, 3L], dtype=object)
In [2]: x
Out[2]: array([1L, 2L, 3L], dtype=object)
In [3]: x[0]
Out[3]: 1L
In [4]: type(x[0])
Out[4]: long
Whether or not this is useful for you depends on what you want to do with the array of longs.
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