I have some hospital data in a dataframe, read in from a csv. I tried to order the dataframe by a user-defined column col
and then by the hospital's name like so:
col <- 'Hospital.30.Day.Death..Mortality..Rates.from.Pneumonia'
hospitals.sorted <- hospitals[order(hospitals[,col], hospitals$Hospital.Name),]
But I think I'm missing something; it seems to sort col
like strings:
> hospitals.sorted
... # so far so good # ...
2749 10.0
2831 10.0
2891 10.0
2837 10.1
2824 10.1
2774 10.1
... # not so good # ...
2856 15.7
2834 15.9
2797 16.0
2835 7.4
2850 7.7
2789 8.1
... # there are some non-numeric values at the very bottom # ...
2806 9.9
2867 9.9
2884 9.9
2808 Not Available
2913 Not Available
2911 Not Available
Just to confirm the column is in fact numeric:
> sapply(hospitals, mode)
Hospital.30.Day.Death..Mortality..Rates.from.Pneumonia
"numeric"
Hospital.Name
"numeric"
I don't know why Hospital.Name
is numeric when it's clearly not.
Other things I tried to no avail:
as.numeric(hospitals[,col])
inside of order
I may be missing something fundamental. Halp!
In data frames, the individual components must be atomic vectors. You are including both numeric and character data in the variable you mention, and as such R will have read that as a character vector. However, due to the default setting of argument stringsAsFactors
that character vector will have been converted to a factor. And hence it will look like the numbers are stored as numerics. Those are just labels however and you are being deceived.
Likewise, the mode()
call is deceiving you too. Consider
> mode(factor(c(1:10, "a")))
[1] "numeric"
Yet this is clearly not "numeric" data. Next consider
> mode(factor(letters))
[1] "numeric"
This belies the fact that internally R's factors are stored as numeric variables and that is what mode()
is telling you. mode()
is the wrong tool for this job.
To test if a variable is numeric, use is.numeric()
instead:
> is.numeric(factor(c(1:10, "a")))
[1] FALSE
> is.numeric(factor(letters))
[1] FALSE
As to the solution. The "Not Available" needs to be set to NA
. You can do this when reading the data in by adding na.strings = "Not Available"
to the read.table()
(or whatever wrapper you used) call. That should be enough to sort out the character > factor conversion.
Top tip is to always look at the output of str()
applied to your object to check that R has read the data in as you wanted it to. So you should do:
str(hospitals)
and note the types of variables according to R.
Regarding the other things you tried:
as.numeric(hospitals[,col])
will produce the numeric vector containing the level ID for each element of the factor. If the factor sorts in a particular order, so will it's levels representation. To convert a factor (it's labelled version) to a numeric you need an intermediate step: as.numeric(as.character(hospitals[, col]))
. This will not solve the actual problem you have here though, because you have character data in the variable and R won't be able to convert it to numeric. It will convert the "Not Available"
to NA
, which might have worked had you tried as.numeric(as.character(hospitals[, col]))
."Not Available"
, I presume by dropping those rows/elements?, will still leave the remaining observations in a factor. Which for reasons mentioned above won't work as it will alpha sort on the labels/levels.If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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