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I have a matrix A. Now I want to find the number of elements greater than 5 and their corresponding indices. How to solve this in matlab without using for loop?
For example if A = [1 4 6 8 9 5 6 8 9]':
[3 4 5 7 8 9]
485
Use COUNTIF to figure cells greater than some chosen figure Now COUNTIF function will count the number of cells in the selected data range that contain a numeric value greater than the specified numeric value in criterion expression and will return the result as a number.
allAreas = [S. Area];
count() lets you quickly count the unique values of one or more variables: df %>% count(a, b) is roughly equivalent to df %>% group_by(a, b) %>% summarise(n = n()) . count() is paired with tally() , a lower-level helper that is equivalent to df %>% summarise(n = n()) .
A = count( str , pat ) returns the number of occurrences of pat in str . If pat is an array containing multiple patterns, then count returns the sum of the occurrences of all elements of pat in str . count matches elements of pat in order, from left to right.
You use find:
index = find(A>5);
numberOfElements = length(index);
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