I have a simple NSURLRequest:
[NSURLConnection sendAsynchronousRequest:myRequest queue:queue completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) { // do stuff with response if status is 200 }];
How do I get the status code to make sure the request was ok?
Cast an instance of NSHTTPURLResponse
from the response and use its statusCode
method.
[NSURLConnection sendAsynchronousRequest:myRequest queue:queue completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) { NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse *) response; NSLog(@"response status code: %ld", (long)[httpResponse statusCode]); // do stuff }];
In Swift with iOS 9 you can do it this way:
if let url = NSURL(string: requestUrl) { let request = NSMutableURLRequest(URL: url, cachePolicy: NSURLRequestCachePolicy.ReloadIgnoringLocalAndRemoteCacheData, timeoutInterval: 300) let config = NSURLSessionConfiguration.defaultSessionConfiguration() let session = NSURLSession(configuration: config) let task = session.dataTaskWithRequest(request, completionHandler: { (data, response, error) -> Void in if let httpResponse = response as? NSHTTPURLResponse { print("Status code: (\(httpResponse.statusCode))") // do stuff. } }) task.resume() }
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