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NSString *url = @"http://stackoverflow.com/questions/ask";
How can I get the character position of the 4th "/" ?
459
(NSString *) is simply the type of the argument - a string object, which is the NSString class in Cocoa. In Objective-C you're always dealing with object references (pointers), so the "*" indicates that the argument is a reference to an NSString object.
NSString : Creates objects that resides in heap and always passed by reference. String: Its a value type whenever we pass it , its passed by value. like Struct and Enum, String itself a Struct in Swift.
If you're just trying to get the last part of the url, you should be able to use this:
NSArray* items = [url componentsSeparatedByString:@"/"];
To get the index of the last '/' character:
NSRange range = [url rangeOfString:@"/" options:NSBackwardsSearch];
get the index value from range.location
To find the index of the fourth '/' character from the url:
int count = 0;
int index = -1;
for (unsigned int i=0; i < [url length]; ++i) {
if ([url characterAtIndex:i] == '/') {
++count;
if (count == 4) {
index = i;
break;
}
}
}
Usually you don't have to get the index of the letter /. You can just use many convenience methods defined in NSURL, see this Apple reference. I would do
NSURL* url=[NSURL URLWithString:@"http://stackoverflow.com/questions/ask"];
NSString* last=[url lastPathComponent]; // last is now @"ask"
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