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I want to use a seed with np.random.permutation, like
np.random.permutation(10, seed=42) I get the following error:
"permutation() takes no keyword arguments" How can I do that else? Thanks.
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The numpy random seed is a numerical value that generates a new set or repeats pseudo-random numbers. The value in the numpy random seed saves the state of randomness. If we call the seed function using value 1 multiple times, the computer displays the same random numbers.
Random Permutations of Elements A permutation refers to an arrangement of elements. e.g. [3, 2, 1] is a permutation of [1, 2, 3] and vice-versa. The NumPy Random module provides two methods for this: shuffle() and permutation() .
To generate random Permutation in Python, then you can use the np random permutation. If the provided parameter is a multi-dimensional array, it is only shuffled along with its first index. If the parameter is an integer, randomly permute np.
seed is a method to fill random. RandomState container. from numpy docs: numpy.random.seed(seed=None) Seed the generator. This method is called when RandomState is initialized.
If you want it in one line, you can create a new RandomState, and call the permutation on that:
np.random.RandomState(seed=42).permutation(10) This is better than just setting the seed of np.random, as it will have only a localized effect.
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np.random.seed(42) np.random.permutation(10) If you want to call np.random.permutation(10) multiple times and get identical results, you also need to call np.random.seed(42) every time you call permutation().
For instance,
np.random.seed(42) print(np.random.permutation(10)) print(np.random.permutation(10)) will produce different results:
[8 1 5 0 7 2 9 4 3 6] [0 1 8 5 3 4 7 9 6 2] while
np.random.seed(42) print(np.random.permutation(10)) np.random.seed(42) print(np.random.permutation(10)) will give the same output:
[8 1 5 0 7 2 9 4 3 6] [8 1 5 0 7 2 9 4 3 6] If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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