I want to use a seed with np.random.permutation
, like
np.random.permutation(10, seed=42)
I get the following error:
"permutation() takes no keyword arguments"
How can I do that else? Thanks.
The numpy random seed is a numerical value that generates a new set or repeats pseudo-random numbers. The value in the numpy random seed saves the state of randomness. If we call the seed function using value 1 multiple times, the computer displays the same random numbers.
Random Permutations of Elements A permutation refers to an arrangement of elements. e.g. [3, 2, 1] is a permutation of [1, 2, 3] and vice-versa. The NumPy Random module provides two methods for this: shuffle() and permutation() .
To generate random Permutation in Python, then you can use the np random permutation. If the provided parameter is a multi-dimensional array, it is only shuffled along with its first index. If the parameter is an integer, randomly permute np.
seed is a method to fill random. RandomState container. from numpy docs: numpy.random.seed(seed=None) Seed the generator. This method is called when RandomState is initialized.
If you want it in one line, you can create a new RandomState
, and call the permutation
on that:
np.random.RandomState(seed=42).permutation(10)
This is better than just setting the seed of np.random
, as it will have only a localized effect.
np.random.seed(42) np.random.permutation(10)
If you want to call np.random.permutation(10)
multiple times and get identical results, you also need to call np.random.seed(42)
every time you call permutation()
.
For instance,
np.random.seed(42) print(np.random.permutation(10)) print(np.random.permutation(10))
will produce different results:
[8 1 5 0 7 2 9 4 3 6] [0 1 8 5 3 4 7 9 6 2]
while
np.random.seed(42) print(np.random.permutation(10)) np.random.seed(42) print(np.random.permutation(10))
will give the same output:
[8 1 5 0 7 2 9 4 3 6] [8 1 5 0 7 2 9 4 3 6]
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