Not able to use Multi Catch from Java Effectively [duplicate]

Question

I really want to use features from Java-1.7. One of this feature is "Multi-Catch". Currently I have the following code

try {
    int Id = Integer.parseInt(idstr);

    TypeInfo tempTypeInfo = getTypeInfo(String.valueOf(Id));

    updateTotalCount(tempTypeInfo);
} catch (NumberFormatException numExcp) {
    numExcp.printStackTrace();
} catch (Exception exception) {
    exception.printStackTrace();
} 

I want to remove the two catch blocks from the above code, and instead use single catch like below:

try {
    int Id = Integer.parseInt(idstr);

    TypeInfo tempTypeInfo = getTypeInfo(String.valueOf(Id));

    updateTotalCount(tempTypeInfo);
} catch (Exception | NumberFormatException ex) { // --> compile time error
    ex.printStackTrace();
} 

But the above code is giving compile time error:

"NumberFormatException" is already caught by the alternative Exception.

I understood the above compile time error but what is the replace for my first block of code.

Answer 1

NumberFormatException is a subclass of Exception. Saying that both catch blocks should have the same behavior is like saying that you don't have any special treatment for NumberFormatException, just the same general treatment you have for Exception. In that case, you can just omit its catch block and only catch Exception:

try {
    int Id = Integer.parseInt(idstr);

    TypeInfo tempTypeInfo = getTypeInfo(String.valueOf(Id));

    updateTotalCount(tempTypeInfo);
} catch (Exception exception) {
    exception.printStackTrace();
} 

Answer 2

The compiler is telling you that

} catch (Exception ex) {

will also catch NumberFormatException exceptions because java.lang.NumberFormatException extends java.lang.IllegalArgumentException, which extends java.lang.RuntimeException, which ultimately extends java.lang.Exception.