non datatype template parameter, more specialization generated?

Question

My Code is:

#include <iostream>

using namespace std;


template <typename T, int X>

class Test
{
   private:
    T container[X];
   public:
    void printSize();

};
template <typename T, int X>
void Test<T,X>::printSize()
{
    cout <<"Container Size = "<<X <<endl;
}


int main()
{
    cout << "Hello World!" << endl;
    Test<int, 20> t;
    Test<int, 30> t1;

    t.printSize();
    t1.printSize();
    return 0;
}

Question:

1. How many specialization will get generated?. If I understand correctly , it generates two specializations one is for <int, 20> and another is for <int, 30>. Kindly Correct if my understanding is wrong?
2. Is there any way to see/check the number of specializations generated by any reverse engineering?

Answer 1

There are not specializations here, only instantiations (this questions explains the difference). This code generates two instantiations of the class template Test.

Answer 2

1) yes, two instantiations will be generated by the compiler, but the linker might merge functions with identical generated code (using whole program optimization e.g.), which is a cute way to reduce code bloat.

2) see this question where it is explained how gcc can generate template instantiation output.