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Is there any clean way to get the contents of text nodes with Nokogiri? Right now I'm using
some_node.at_xpath( "//whatever" ).first.content
which seems really verbose for just getting text.
831
You want only the text?
doc.search('//text()').map(&:text)
Maybe you don't want all the whitespace and noise. If you want only the text nodes containing a word character,
doc.search('//text()').map(&:text).delete_if{|x| x !~ /\w/}
Edit: It appears you only wanted the text content of a single node:
some_node.at_xpath( "//whatever" ).text
Just look for text nodes:
require 'nokogiri'
doc = Nokogiri::HTML(<<EOT)
<html>
<body>
<p>This is a text node </p>
<p> This is another text node</p>
</body>
</html>
EOT
doc.search('//text()').each do |t|
t.replace(t.content.strip)
end
puts doc.to_html
Which outputs:
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body>
<p>This is a text node</p>
<p>This is another text node</p>
</body></html>
BTW, your code example doesn't work. at_xpath( "//whatever" ).first is redundant and will fail. at_xpath will find only the first occurrence, returning a Node. first is superfluous at that point, if it would work, but it won't because Node doesn't have a first method.
I have
<data><foo>bar</foo></bar>, how I get at the "bar" text without doingdoc.xpath_at( "//data/foo" ).children.first.content?
Assuming doc contains the parsed DOM:
doc.to_xml # => "<?xml version=\"1.0\"?>\n<data>\n <foo>bar</foo>\n</data>\n"
Get the first occurrence:
doc.at('foo').text # => "bar"
doc.at('//foo').text # => "bar"
doc.at('/data/foo').text # => "bar"
Get all occurrences and take the first one:
doc.search('foo').first.text # => "bar"
doc.search('//foo').first.text # => "bar"
doc.search('data foo').first.text # => "bar"
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