I'm trying to implementing this mysql command on sequelize, but as far as i'm newbie to use this library i can't implementing that
i want to make this sql command:
SELECT * FROM users
join users_contacts_lists on users_contacts_lists.mobile_number = users.mobile_number
WHERE users_contacts_lists.user_id = 1
My models to create database schema:
'use strict';
var config = require('../config');
var User = config.sequelize.define('users', {
id: {
type: config.Sequelize.INTEGER,
autoIncrement: true,
primaryKey: true
},
password: {
type: config.Sequelize.STRING
},
username: {
type: config.Sequelize.STRING
},
mobileNumber: {
type: config.Sequelize.STRING,
field: 'mobile_number'
},
status: {
type: config.Sequelize.STRING
},
}, {freezeTableName: true});
var UsersContactsLists = config.sequelize.define('users_contacts_lists', {
id: {
type: config.Sequelize.INTEGER,
autoIncrement: true,
primaryKey: true
},
userId: {
type: config.Sequelize.INTEGER,
field: 'user_id'
},
mobileNumber: {
type: config.Sequelize.STRING,
field: 'mobile_number', defaultValue: 0
}
}, {freezeTableName: true});
UsersContactsLists.belongsTo(ChannelsTypes, {foreignKey: 'user_id'});
User.hasMany(Channels, {foreignKey: 'id'});
User.sync();
UsersContactsLists.sync();
module.exports =
{
users: User,
usersContactsLists: UsersContactsLists
};
how can i resolve this problem? Thanks in advance
You can define the target key and the foreign key both in a relation like this:
User.belongsTo(UsersContactsLists, {targetKey:'mobileNumber',foreignKey: 'mobileNumber'});
And then you can use this:
User.findAll({
include: [{
model: UsersContactsLists,
where: {
userId: 1
}
}]
})
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