nodejs load file

Question

I want to load test.txt with nodejs.

var fs = require('fs'); fs.readFile('./test.txt', function (err, data) {   if (err) {     throw err;    }   console.log(data); }); 

The path of the server is C:\server\test\server.js. The test.txt is located in the same directory, but I get this error: Error: ENOENT, no such file or directory 'C:\Users\User\test.txt'

Answer 1

Paths in Node are resolved relatively to the current working directory. Prefix your path with __dirname to resolve the path to the location of your Node script.

var fs = require('fs'); fs.readFile( __dirname + '/test.txt', function (err, data) {   if (err) {     throw err;    }   console.log(data.toString()); }); 

Answer 2

With Node 0.12, it's possible to do this synchronously now:

  var fs = require('fs');   var path = require('path');    // Buffer mydata   var BUFFER = bufferFile('../test.txt');    function bufferFile(relPath) {     return fs.readFileSync(path.join(__dirname, relPath)); // zzzz....   } 

fs is the file system. readFileSync() returns a Buffer, or string if you ask.

fs correctly assumes relative paths are a security issue. path is a work-around.

To load as a string, specify the encoding:

return fs.readFileSync(path,{ encoding: 'utf8' });