nodejs equivalent of this .htaccess

Question

Is it possible to build a code like this in node.js?

<IfModule mod_rewrite.c>
     RewriteEngine on

     RewriteCond% {REQUEST_URI}! / (View) / [NC]
     RewriteCond% {REQUEST_FILENAME}!-F
     RewriteRule ^ (. *) $ Index.html [L, QSA]

</IfModule>

url display a route is not "view" and also the file does not exist then write index.html.

using something like express or connect

UPDATE: I need a regular expression for !/(view)/ in route for express in node.js.

Answer 1

Have you tried:

1. Serve statics
2. Catch /view URL

3. Catch everything else

   app.configure(function(){
     app.use(express.static(__dirname+'/public')); // Catch static files
     app.use(app.routes);
   });
   
   // Catch /view and do whatever you like
   app.all('/view', function(req, res) {
   
   });
   
   // Catch everything else and redirect to /index.html
   // Of course you could send the file's content with fs.readFile to avoid
   // using redirects
   app.all('*', function(req, res) { 
     res.redirect('/index.html'); 
   });
   

OR

1. Serve statics

2. Check if URL is /view

   app.configure(function(){
     app.use(express.static(__dirname+'/public')); // Catch static files
     app.use(function(req, res, next) {
       if (req.url == '/view') {
         next();
       } else {
         res.redirect('/index.html');
       }
     });
   });
   

OR

1. Catch statics as usual

2. Catch NOT /view

   app.configure(function(){
     app.use(express.static(__dirname+'/public')); // Catch static files
     app.use(app.routes);
   });
   
   app.get(/^(?!\/view$).*$/, function(req, res) {
     res.redirect('/index.html');
   });