Node child_process.spawn multiple commands

Question

I wan to automate the creation and extracting of keystore. The problem I'm facing is how to join the commands using the ' | ' symbol or similar solution.

//Original Command     var command='keytool -exportcert -storepass mypass -keypass mypass   -alias myalias -keystore mykey.keystore | openssl sha1 -binary | openssl base64';  //Arguments for the spawn     var keyArgs = [       '-exportcert',       '-storepass','mypass',       '-keypass','mypass',       '-alias','myalias',       '-keystore',"myjey.keystore",         'openssl','sha1',       '-binary',       'openssl','base64',     ]; exec('keytool',keyArgs,{cwd:appCreateFolder+"/"+opt.id+"/Certificates"},function(e){     console.log(chalk.cyan('Key created'));       }) 

Answer 1

From Node.js v6 you can specify a shell option in spawn method which will run command using shell and thus it is possible to chain commands using spawn method.

For example this:

var spawn = require('child_process').spawn; var child = spawn('ls && ls && ls', {   shell: true }); child.stderr.on('data', function (data) {   console.error("STDERR:", data.toString()); }); child.stdout.on('data', function (data) {   console.log("STDOUT:", data.toString()); }); child.on('exit', function (exitCode) {   console.log("Child exited with code: " + exitCode); }); 

Will trigger an error on node.js version less than 6:

Error: spawn ls && ls && ls ENOENT 

But on version 6 and higher it will return expected result:

node app.js STDOUT: app.js  STDOUT: app.js app.js  Child exited with code: 0