I am trying create an project with and without spring xml configurations.
First at all, I create my xml configuration like that:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.1.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-4.1.xsd">
<bean id="memoryManagerProduct" class="br.com.caelum.stock.ProductManager">
<constructor-arg ref="memoryProductDAO"/>
</bean>
<bean id="memoryProductDAO" class="br.com.caelum.stock.dao.MemoryProductDAO"/>
</beans>
That I created my non XML configuration (I do not know if is right base in the fact that I do not know how invoke that)
package br.com.caelum.spring.config;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import br.com.caelum.stock.ProductManager;
import br.com.caelum.stock.dao.MemoryProductDAO;
import br.com.caelum.stock.dao.Persistable;
import br.com.caelum.stock.model.Product;
@Configuration
public class AppConfig {
@Bean
public Persistable<Product> memoryProductDAO(){
return new MemoryProductDAO();
}
@Bean
public ProductManager memoryProductManager(){
return new ProductManager(memoryProductDAO());
}
}
Than I created an JUnit test:
package br.com.caelum.stock;
import static org.hamcrest.CoreMatchers.is;
import static org.junit.Assert.assertThat;
import org.junit.Test;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import br.com.caelum.stock.model.Product;
public class ProductManagerTest {
private ProductManager manager;
@Test
public void testSpringXMLConfiguration() {
ApplicationContext context = new ClassPathXmlApplicationContext("classpath:spring.xml");
manager = (ProductManager) context.getBean("memoryManagerProduct");
Product product = new Product();
product.setDescription("[Book] Spring in Action");
product.setQuantity(10);
manager.add(product);
assertThat(manager.getProducts().get(0).getDescription(), is("[Book] Spring in Action"));
}
@Test
public void testSpringWithoutXMLConfiguration() {
ApplicationContext context = ?
}
}
How can I inject the configurations that are in my AppConfig to do a similar test as in my testSpringXMLConfiguration?
There are good examples in the Spring reference guide here: http://docs.spring.io/spring/docs/current/spring-framework-reference/html/beans.html#beans-java-instantiating-container
In short, you would do this:
ApplicationContext context = new AnnotationConfigApplicationContext(AppConfig.class);
manager = (ProductManager) context.getBean("memoryManagerProduct");
However a better way of testing with Spring would be to use the spring-test support, details are here - http://docs.spring.io/spring/docs/current/spring-framework-reference/html/testing.html#integration-testing-annotations
You can do something like this with spring-test support:
@ContextConfiguration(classes = AppConfig.class)
@RunWith(SpringJUnit4ClassRunner.class)
public class ProductManagerTest {
@Autowired
private ProductManager manager;
@Test
public void testSpringXMLConfiguration() {
//use the productmanager in a test..
}
}
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With