Is there a built in method in .NET to convert a number to the string representation of the number? For example, 1 becomes one, 2 becomes two, etc.
To convert an integer to string in C#, use the ToString() method.
Converting Numerics to Strings The str() function can be used to change any numeric type to a string.
ToString(Double, IFormatProvider) Converts the value of the specified double-precision floating-point number to its equivalent string representation.
I've always been a fan of the recursive method
public static string NumberToText( int n)
{
if ( n < 0 )
return "Minus " + NumberToText(-n);
else if ( n == 0 )
return "";
else if ( n <= 19 )
return new string[] {"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight",
"Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen",
"Seventeen", "Eighteen", "Nineteen"}[n-1] + " ";
else if ( n <= 99 )
return new string[] {"Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy",
"Eighty", "Ninety"}[n / 10 - 2] + " " + NumberToText(n % 10);
else if ( n <= 199 )
return "One Hundred " + NumberToText(n % 100);
else if ( n <= 999 )
return NumberToText(n / 100) + "Hundreds " + NumberToText(n % 100);
else if ( n <= 1999 )
return "One Thousand " + NumberToText(n % 1000);
else if ( n <= 999999 )
return NumberToText(n / 1000) + "Thousands " + NumberToText(n % 1000);
else if ( n <= 1999999 )
return "One Million " + NumberToText(n % 1000000);
else if ( n <= 999999999)
return NumberToText(n / 1000000) + "Millions " + NumberToText(n % 1000000);
else if ( n <= 1999999999 )
return "One Billion " + NumberToText(n % 1000000000);
else
return NumberToText(n / 1000000000) + "Billions " + NumberToText(n % 1000000000);
}
Source
Ah, there may not be a class to do this, but there was a code golf question which I provided a C# example for:
Code Golf: Number to Words
However, it's not the easiest to read and it only goes up to decimal.MaxValue, so I've written a new version that will go as high as you need to.
I couldn't find any information regarding values higher than vigintillions, but if you append the values to the thou[] array, you can continue going up as far as you like. It still doesn't support fractions, but I'm thinking about adding that at some point.
static string NumericStringToWords(string NumericValue)
{
if ("0" == NumericValue) return "zero";
string[] units = { "one", "two", "three", "four", "five",
"six", "seven", "eight", "nine" };
string[] teens = { "eleven", "twelve", "thirteen", "four", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen" };
string[] tens = { "ten", "twenty", "thirty", "forty", "fifty",
"sixty", "seventy", "eighty", "ninety" };
string[] thou = { "thousand", "million", "billion", "trillion",
"quadrillion", "quintillion", "sextillion",
"septillion", "octillion", "nonillion", "decillion",
"udecillion", "duodecillion", "tredecillion",
"quattuordecillion", "quindecillion", "sexdecillion",
"septendecillion", "octodecillion", "novemdecillion",
"vigintillion" };
string sign = String.Empty;
if ("-" == NumericValue.Substring(0, 1))
{
sign = "minus ";
NumericValue = NumericValue.Substring(1);
}
int maxLen = thou.Length * 3;
int actLen = NumericValue.Length;
if(actLen > maxLen)
throw new InvalidCastException(String.Format("{0} digit number specified exceeds the maximum length of {1} digits. To evaluate this number, you must first expand the thou[] array.", actLen, maxLen));
//Make sure that the value passed in is indeed numeric... we parse the entire string
//rather than just cast to a numeric type to allow us to handle large number types passed
//in as a string. Otherwise, we're limited to the standard data type sizes.
int n; //We don't care about n, but int.TryParse requires it
if (!NumericValue.All(c => int.TryParse(c.ToString(), out n)))
throw new InvalidCastException();
string fraction = String.Empty;
if (NumericValue.Contains("."))
{
string[] split = NumericValue.Split('.');
NumericValue = split[0];
fraction = split[1];
}
StringBuilder word = new StringBuilder();
ulong loopCount = 0;
while (0 < NumericValue.Length)
{
int startPos = Math.Max(0, NumericValue.Length - 3);
string crntBlock = NumericValue.Substring(startPos);
if (0 < crntBlock.Length)
{
//Grab the hundreds tens & units for the current block
int h = crntBlock.Length > 2 ? int.Parse(crntBlock[crntBlock.Length - 3].ToString()) : 0;
int t = crntBlock.Length > 1 ? int.Parse(crntBlock[crntBlock.Length - 2].ToString()) : 0;
int u = crntBlock.Length > 0 ? int.Parse(crntBlock[crntBlock.Length - 1].ToString()) : 0;
StringBuilder thisBlock = new StringBuilder();
if (0 < u)
thisBlock.Append(1 == t? teens[u - 1] : units[u - 1]);
if (1 != t)
{
if (1 < t && 0 < u) thisBlock.Insert(0, "-");
if (0 < t) thisBlock.Insert(0, tens[t - 1]);
}
if (0 < h)
{
if (t > 0 | u > 0) thisBlock.Insert(0, " and ");
thisBlock.Insert(0, String.Format("{0} hundred", units[h - 1]));
}
//Check to see if we've got any data left and add
//appropriate word separator ("and" or ",")
bool MoreLeft = 3 < NumericValue.Length;
if (MoreLeft && (0 == h) && (0 == loopCount))
thisBlock.Insert(0, " and ");
else if (MoreLeft)
thisBlock.Insert(0, String.Format(" {0}, ", thou[loopCount]));
word.Insert(0, thisBlock);
}
//Remove the block we just evaluated from the
//input string for the next loop
NumericValue = NumericValue.Substring(0, startPos);
loopCount++;
}
return word.Insert(0, sign).ToString();
}
I tested it using Decimal.MaxValue appended to itself to generate a large number of:
seven octodecillion, nine hundred and twenty-two septendecillion, eight hundred and sixteen sexdecillion, two hundred and fifty-one quindecillion, four hundred and twenty-six quattuordecillion, four hundred and thirty-three tredecillion, seven hundred and fifty-nine duodecillion, three hundred and fifty-four udecillion, three hundred and ninety-five decillion, thirty-three nonillion, five hundred and seventy-nine octillion, two hundred and twenty-eight septillion, one hundred and sixty-two sextillion, five hundred and four quintillion, two hundred and sixty-four quadrillion, three hundred and thirty-seven trillion, five hundred and ninety-three billion, five hundred and forty-three million, nine hundred and fifty- thousand, three hundred and thirty-five
public string IntToString(int number)//nobody really uses negative numbers
{
if(number == 0)
return "zero";
else
if(number == 1)
return "one";
.......
else
if(number == 2147483647)
return "two billion one hundred forty seven million four hundred eighty three thousand six hundred forty seven";
}
Here is the modified code I used:
//Wrapper class for NumberToText(int n) to account for single zero parameter.
public static string ConvertToStringRepresentation(long number)
{
string result = null;
if (number == 0)
{
result = "Zero";
}
else
{
result = NumberToText(number);
}
return result;
}
//Found at http://www.dotnet2themax.com/blogs/fbalena/PermaLink,guid,cdceca73-08cd-4c15-aef7-0f9c8096e20a.aspx.
//Modifications from original source:
// Changed parameter type from int to long.
// Changed labels to be singulars instead of plurals (Billions to Billion, Millions to Million, etc.).
private static string NumberToText(long n)
{
if (n < 0)
return "Minus " + NumberToText(-n);
else if (n == 0)
return "";
else if (n <= 19)
return new string[] {"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight",
"Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen",
"Seventeen", "Eighteen", "Nineteen"}[n - 1] + " ";
else if (n <= 99)
return new string[] {"Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy",
"Eighty", "Ninety"}[n / 10 - 2] + " " + NumberToText(n % 10);
else if (n <= 199)
return "One Hundred " + NumberToText(n % 100);
else if (n <= 999)
return NumberToText(n / 100) + "Hundred " + NumberToText(n % 100);
else if (n <= 1999)
return "One Thousand " + NumberToText(n % 1000);
else if (n <= 999999)
return NumberToText(n / 1000) + "Thousand " + NumberToText(n % 1000);
else if (n <= 1999999)
return "One Million " + NumberToText(n % 1000000);
else if (n <= 999999999)
return NumberToText(n / 1000000) + "Million " + NumberToText(n % 1000000);
else if (n <= 1999999999)
return "One Billion " + NumberToText(n % 1000000000);
else
return NumberToText(n / 1000000000) + "Billion " + NumberToText(n % 1000000000);
}
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