Need help with C++ Loops Exercise

Question

From Cay Horstmann's "C++ For Everyone" Chapter 4: Loops

Write a program that adds up the sum of all odd digits of n. (For example, if n is 32677, the sum would be 3 + 7 + 7 = 17)

I don't know how to make the computer "see" the numbers like separate them

Answer 1

n % 10 gets the value of the one's digit. You can figure it out from there right?

Answer 2

Here's a hint. C++ has the modulus operator %. It will produce the remainder when two numbers are divided together. So if I wanted to know the last digit in a number which was greater than 10 I would modulus 10 and get the result

int lastDigit = number % 10;

Answer 3

The last digit of a base-10 integer i is equal to i % 10. (For reference, % is the modulus operator; it basically returns the remainder from dividing the left number by the right.)

So, now you have the last digit. Once you do, add it to a running total you're keeping, divide i by 10 (effectively shifting the digits down by one place), or in your case 100 (two places), and start back at the beginning. Repeat until i == 0.