namespaces having unnamed namespace with the same variable declared

Question

I tried this dummy code below to test unnamed namespace.

I have the following output

 ctor 1
 ctor 0
 3
 5

I am a bit confused about this.

1. I was expecting an error from the compiler saying that it cannot resolve an ambiguity regarding a::m_a. Instead it refers always to the less nested. Is it always the case? What rules C++ is following?
2. It seems that the compiler creates variable CMyObj following the order written on the file. Is this always the case?
3. is there any way to access the most nested m_a variable from main()?.

class CMyObj{     
    public:
    CMyObj(int a){std::cout  << "ctor " << a << std::endl; }
 };
 namespace a{ 
      namespace{
           int m_a=4;
           int m_b=5;
           CMyObj m_obj(1);
      }  
 }
 namespace a{
      int m_a=3;
      CMyObj m_obj(0);
 }
 int main(){
      std::cout << a::m_a << std::endl; // which one?
      std::cout << a::m_b << std::endl; // how this is possible?
      return 0;
 }

Answer 1

I don't have C++03 standard with me to check the wording there, so I will quote from FDIS n3290. I think the answer to this question is found in qualified name lookup rules in 3.4.3.2/2:

For a namespace X and name m, the namespace-qualified lookup set S(X,m) is defined as follows: Let S0(X,m) be the set of all declarations of m in X and the inline namespace set of X (7.3.1). If S0(X,m) is not empty, S(X,m) is S0(X,m); otherwise, S(X,m) is the union of S(Ni,m) for all namespaces Ni nominated by using-directives in X and its inline namespace set.

Now, remember that unnamed namespace is a uniquely named namespace with a using directive.