Mysql where id is in array [duplicate]

Question

I have a string of ids like 1,2,3,4,5 and I want to be able to list all rows in mysql where the ID is contained in that list.

I assumed the easiest way would be to turn the string into an array and then match in ($array) but it doesn't work for me - no errors etc but it returns no rows:

$string="1,2,3,4,5"; $array=array_map('intval', explode(',', $string)); $query=mysqli_query($conn, "SELECT name FROM users WHERE id IN ('".$array."')"); 

If I do a var_dump of $array I get:

array(5) {      [0]=> int(1)      [1]=> int(2)      [2]=> int(3)      [3]=> int(4)      [4]=> int(5)  } 

Any idea where I am screwing up?

Answer 1

$string="1,2,3,4,5"; $array=array_map('intval', explode(',', $string)); $array = implode("','",$array); $query=mysqli_query($conn, "SELECT name FROM users WHERE id IN ('".$array."')"); 

NB: the syntax is:

SELECT * FROM table WHERE column IN('value1','value2','value3')