I have a table with each row containing a date and some arbitrary, numeric value. I need to sum this value for a specific but dynamic date interval.
SELECT VERSION();
5.0.51a-24+lenny5
CREATE TABLE IF NOT EXISTS `work_entries` (
`entry_id` int(10) unsigned NOT NULL auto_increment,
`employee_id` tinyint(3) unsigned NOT NULL,
`work_date` date NOT NULL,
`hour_count` tinyint(3) unsigned NOT NULL,
PRIMARY KEY (`entry_id`)
);
INSERT INTO `work_entries` (`entry_id`, `employee_id`, `work_date`, `hour_count`) VALUES
(1, 1, '2011-04-25', 2),
(2, 1, '2011-04-26', 3),
(3, 1, '2011-04-27', 1),
(4, 2, '2011-04-25', 2),
(5, 2, '2011-04-27', 4),
(6, 1, '2011-05-08', 2),
(7, 2, '2011-05-06', 8),
(8, 2, '2011-05-08', 9),
(9, 2, '2011-05-09', 1),
(10, 1, '2011-05-29', 3),
(11, 1, '2011-05-30', 1),
(12, 2, '2011-05-30', 2),
(13, 1, '2011-06-02', 2),
(14, 1, '2011-06-04', 3),
(15, 1, '2011-06-14', 1),
(16, 2, '2011-06-14', 2),
(17, 2, '2011-06-17', 4),
(18, 1, '2011-06-18', 2),
(19, 2, '2011-06-19', 8),
(20, 2, '2011-06-26', 9),
(21, 2, '2011-07-01', 1),
(22, 1, '2011-07-03', 3),
(23, 1, '2011-07-03', 1),
(24, 2, '2011-07-16', 2);
The following query returns the correct output for the above data set and should illustrate what I'm trying to do, however, I need to generate the year and month values based on work_date
. The days (16, 15) never change. Specifically, this query will produce two rows, one for the specified interval and one for the rest, where I need one row for each period (16th of month N to 15th of month N+1 for all months with values).
SELECT
SUM(hour_count) AS res
FROM `work_entries`
GROUP BY work_date
BETWEEN '2011-04-16' AND '2011-05-15';
-- Outputs
res
----
44
32
-- Should give
res
----
32
14
28
2
An alternative example that works correctly but on the wrong interval (days 01-31):
SELECT
SUM(hour_count) AS res
FROM `work_entries`
GROUP BY MONTH(work_date);
-- Outputs
res
---
12
26
31
7
Additionally, if there is a way to output the from- and to- dates at the same time I'd like that as well, but that's not very important.
You can use the SUM() function in a SELECT with JOIN clause to calculate the sum of values in a table based on a condition specified by the values in another table.
The SUM() function returns the total sum of a numeric column.
MySQL Date Data Types DATE - format YYYY-MM-DD. DATETIME - format: YYYY-MM-DD HH:MI:SS. TIMESTAMP - format: YYYY-MM-DD HH:MI:SS. YEAR - format YYYY or YY.
MONTH() function in MySQL is used to find a month from the given date. It returns 0 when the month part for the date is 0 otherwise it returns month value between 1 and 12. date : The date or DateTime from which we want to extract the month.
lovely:
SELECT
SUM(hour_count)
FROM `work_entries`
GROUP BY
YEAR(work_date - INTERVAL 15 DAY),
MONTH(work_date - INTERVAL 15 DAY);
SELECT
YEAR(grouping_date) AS year,
MONTH(grouping_date) AS month,
SUM(hour_count) AS hour_count_total
FROM (
SELECT
work_date,
hour_count,
work_date - INTERVAL 15 DAY AS grouping_date
FROM work_entries
) x
GROUP BY
YEAR(grouping_date),
MONTH(grouping_date)
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