I am building a query in mysql 5.0 to calculate a student semester grade. The initial table (studentItemGrades) contains the list of assignments etc which will be used to calculate the final grade. Each assignment has a PossibleScore, Grade and Weight. The calculation should group all similarly weighted items, and provide the SUM(GRADE)/SUM(POSSIBLESCORE) based on a date range of when the assignment was due. The problem I am encountering is the final summation of all the individual weighted grades. For example, the results currently produce the following:
CourseScheduleID sDBID AssignedDate DueDate Weight WeightedGrade
1 519 2010-08-26 2010-08-30 10 0.0783333333333333
1 519 2010-09-01 2010-09-03 20 0.176
1 519 2010-09-01 2010-09-10 70 0.574
from the query:
SELECT CourseScheduleID, sDBID, AssignedDate, DueDate, Weight,
((SUM(Grade)/SUM(PossibleScore))*(Weight/100)) AS WeightedGrade
FROM studentItemGrades
WHERE DueDate>='2010-08-23'
AND DueDate<='2010-09-10'
AND CourseScheduleID=1
AND sDBID=519
AND Status>0
GROUP BY Weight
The question: How do I now SUM the three results in the WeighedGrade output? And by the way, this is part of a much larger query for calculating all grades for all courses on a particular campus.
Thanks in advance for your help.
Example: MySQL SUM() function using multiple columnsMySQL SUM() function retrieves the sum value of an expression which is made up of more than one columns. The above MySQL statement returns the sum of multiplication of 'receive_qty' and 'purch_price' from purchase table for each group of category ('cate_id') .
If you need to add a group of numbers in your table you can use the SUM function in SQL. This is the basic syntax: SELECT SUM(column_name) FROM table_name; If you need to arrange the data into groups, then you can use the GROUP BY clause.
like this $sum= mysql_query("SELECT SUM(Value) FROM Codes"); with this i get Resource id #10 but not the sum of all values. Try $result = mysql_query('SELECT SUM(value) AS value_sum FROM codes'); $row = mysql_fetch_assoc($result); $sum = $row['value_sum']; .
You can use a subquery, like so:
SELECT SUM(WeightedGrade) FROM
(
SELECT CourseScheduleID, sDBID, AssignedDate, DueDate, Weight,
((SUM(Grade)/SUM(PossibleScore))*(Weight/100)) AS WeightedGrade
FROM studentItemGrades
WHERE DueDate>='2010-08-23'
AND DueDate<='2010-09-10'
AND CourseScheduleID=1
AND sDBID=519
AND Status>0
GROUP BY Weight
) t1
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