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I am trying to select a row with a distinct id, yet return all the fields.
SELECT * DISTINCT(ID) FROM table WHERE ...
I ultimately need the ID, City, State and Zip. How can I get rows that are not duplicate ID's and return all fields into my mysql_fetch_array?
I have tried the following:
SELECT * DISTINCT(ID) FROM table WHERE ...
SELECT DISTINCT ID * FROM table WHERE ...
SELECT ID,City,State,Zip DISTINCT ID FROM ...
SELECT ID,City,State,Zip DISTINCT(ID) FROM ...
I was reading other questions here and none seem to help. Thanks in advance!
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The SQL SELECT DISTINCT Statement The SELECT DISTINCT statement is used to return only distinct (different) values. Inside a table, a column often contains many duplicate values; and sometimes you only want to list the different (distinct) values.
You can use the DISTINCT command along with the SELECT statement to find out unique records available in a table. mysql> SELECT DISTINCT last_name, first_name -> FROM person_tbl -> ORDER BY last_name; An alternative to the DISTINCT command is to add a GROUP BY clause that names the columns you are selecting.
The SELECT statement is used to select data from a database. The data returned is stored in a result table, called the result-set.
The go to solution for removing duplicate rows from your result sets is to include the distinct keyword in your select statement. It tells the query engine to remove duplicates to produce a result set in which every row is unique.
Try using GROUP BY:
select id, city, state, zip from mytable group by id Note that this will return an arbitrary address for each id if there are duplicates.
Demo: http://www.sqlfiddle.com/#!2/c0eba/1
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