MySQL - SELECT the name that comes first alphabetically

Question

I have started to learn MySQL.

Here is the table world:

+-------------+-----------+---------+
|    name     | continent |  area   |
+-------------+-----------+---------+
| Afghanistan | Asia      | 652230  |
| Albania     | Europe    | 2831741 |
| Algeria     | Africa    | 28748   |
| ...         | ...       | ...     |
+-------------+-----------+---------+

I need:

List each continent and the name of the country that comes first alphabetically

The result of SELECT must be:

+---------------+---------------------+
|   continent   |         name        |
+---------------+---------------------+
| Africa        | Algeria             |
| Asia          | Afghanistan         |
| Caribbean     | Antigua and Barbuda |
| Eurasia       | Armenia             |
| Europe        | Albania             |
| North America | Belize              |
| Oceania       | Australia           |
| South America | Argentina           |
+---------------+---------------------+

Answer 1

This is a simple aggegation:

SELECT continent, MIN(name) AS name
FROM world 
GROUP BY continent
ORDER by continent

Answer 2

If it's an Exercise from SQLZoo, than IMO it should look something like this:

select continent, name from world x
where name = (select name 
                  from world y 
                  where  x.continent =  y.continent 
                  order by name asc 
                  limit 1)

P.S. I study SQL from there now and this post helped me. Thanks to @Parado!)

Update: I've found this site with answers. Useful if stack.