How to Select All Records from One Table That Do Not Exist in Another Table in SQL? We can get the records in one table that doesn't exist in another table by using NOT IN or NOT EXISTS with the subqueries including the other table in the subqueries.
As you can see is in the above diagram, the MINUS operator will return only those rows which are present in the result set from Table1 and not present in the result set of Table2. Basic Syntax: SELECT column1 , column2 , ...
You need to do the subselect based on a column name, not *
.
For example, if you had an id
field common to both tables, you could do:
SELECT * FROM Table1 WHERE id NOT IN (SELECT id FROM Table2)
Refer to the MySQL subquery syntax for more examples.
If you have 300 columns as you mentioned in another comment, and you want to compare on all columns (assuming the columns are all the same name), you can use a NATURAL LEFT JOIN
to implicitly join on all matching column names between the two tables so that you don't have to tediously type out all join conditions manually:
SELECT a.*
FROM tbl_1 a
NATURAL LEFT JOIN tbl_2 b
WHERE b.FirstName IS NULL
SELECT *
FROM Table1 AS a
WHERE NOT EXISTS (
SELECT *
FROM Table2 AS b
WHERE a.FirstName=b.FirstName AND a.LastName=b.Last_Name
)
EXISTS
will help you...
A standard LEFT JOIN could resolve the problem and, if the fields on join are indexed,
should also be faster
SELECT *
FROM Table1 as t1 LEFT JOIN Table2 as t2
ON t1.FirstName = t2.FirstName AND t1.LastName=t2.LastName
WHERE t2.BirthDate Is Null
Try this simple query. It works perfectly.
select * from Table1 where (FirstName,LastName,BirthDate) not in (select * from Table2);
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