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MySQL select random row with JOIN from two tables

Tags:

php

mysql

I've been searching for a solution to this problem for a few days now and could not find anything that would reduce the time it takes to run the query.

I have 2 tables:

"product_db":  
unique_id - [index] 
image 
url_title 
status - [index]

"product_page"
id
product_unique_id - [index]
page_id - [index]

What I want to select is a random image from product_db where status = 'Online' and the product must be in page id = 3

product_db has over 90,000 products and product_page has over 150000 rows.

The query that I am using now is:

SELECT image FROM product_db a, product_page b WHERE b.page_id = 3 AND a.status = 'Online' AND a.unique_id = b.product_unique_id ORDER BY RAND() LIMIT 1

This query takes around 2.3secs to run. This is quite a long time for a web page to load. I have tried a few other queries that first returns a random row from product_page with page_id = 3 and then querying product_db (it did reduce the time it takes) but the problem with that is I cannot compare if the product is 'Online' or not.

like image 729
James Avatar asked Feb 25 '23 19:02

James


1 Answers

It's the sorting that's slowing you down. Rather than sorting by random, just select a random product_db.unique_id

In your query, replace ORDER BY RAND() with:

AND product_db.unique_id >= ROUND(RAND()*(SELECT MAX(unique_id) FROM product_db))

using >= instead of = in case that unique_id has been deleted from the database. Not as random a result as ordering by rand but the query will execute much faster. If you wish, you can run multiple queries with = until a result is found and it still may be quite faster than sorting all those results.

With an explicit JOIN it would be:

SELECT product_db.image
FROM product_db
JOIN product_page ON product_db.unique_id = product_page.product_unique_id
WHERE product_page.page_id = 3 
AND product_db.status = 'Online' 
AND product_db.unique_id >= ROUND(RAND()*(SELECT MAX(unique_id) FROM product_db))
LIMIT 1
like image 74
webbiedave Avatar answered Mar 02 '23 00:03

webbiedave