MYSQL select DISTINCT values in two columns

Question

I want to select distinct values in a database. Let me run you through a quick example.

Table:

foo bar
--- ---
a   c
c   f
d   a
c   a
f   c
a   c
d   a
a   c
c   a
f   c

Right, let's say my SQL is SELECT DISTINCT foo, bar from table. These are my results:

foo bar
--- ---
a   c
c   f
d   a
c   a
f   c

However the problem is is that there are repetitions of a c / c a just that they are in a different order. I don't want to select these, I want distinct values from both columns, please help!

Answer 1

How about using GROUP BY?

SELECT foo,bar FROM my_table GROUP BY foo,bar

Answer 2

very very wicked & evil:

select distinct
    least(foo, bar) as value1
  , greatest(foo, bar) as value2
from table

Answer 3

How about :

SELECT DISTINCT a.foo,a.bar 
FROM table a
LEFT JOIN table b ON a.foo=b.bar and a.bar=b.foo
WHERE b.foo IS NULL AND b.bar IS NULL

Output :

foo bar
--- ---
d   a

Answer 4

You're asking for something that's the opposite of a symmetric closure (I don't know if it has a special name; antisymmetric something, since it's not a closure). For closures and closure like things where you need to compare two different columns, you can use joins. To make sure you don't filter out both rows when they are duplicated across columns, you need to a way to differentiate the repeats and include one of them, such as by including the pair where the first is the lesser.

SELECT DISTINCT t1.foo, t1.bar
  FROM `table` t1
    LEFT JOIN `table` t2
      ON t1.foo=t2.bar AND t1.bar=t2.foo 
  WHERE t2.foo IS NULL OR t1.foo <= t1.bar;

Answer 5

   SELECT 
       foo, bar
   FROM tableX
   WHERE foo <= bar
 UNION 
   SELECT 
       bar, foo
   FROM tableX
   WHERE bar < foo

Answer 6

SELECT DISTINCT foo, bar FROM table WHERE
CONCAT(',',foo,bar,) NOT IN ( SELECT CONCAT(',',bar,foo) FROM table )

Answer 7

This works for me:

SELECT DISTINCT
LEAST(sub.foo, sub.bar) as value_1
, GREATEST(sub.foo, sub.bar) as value_2

FROM
(SELECT
a.foo
,a.bar
FROM
table a
JOIN
table b
on a.foo = b.bar
and a.bar = b.foo) sub