This query:
SELECT COUNT(source) AS count
FROM call_details
GROUP BY source
HAVING count >1
Returns about 1500 (the number I'm looking for) results with only the count field. How could I also return the sum of all count fields? When I try
SELECT COUNT(source) AS count,
SUM(count) as total
FROM call_details
GROUP BY source
HAVING count >1
I get an 'Unknown column 'count' in 'field list' error.
And
SELECT COUNT(source) AS count,
SUM(COUNT(source)) as total
FROM call_details
GROUP BY source
HAVING count >1
gives me an 'Invalid use of group function'
Any ideas? I can do a mysql_num_rows($result)
of the first set (to get the info I need) but I really want to do it through MySQL.
To counts all of the rows in a table, whether they contain NULL values or not, use COUNT(*). That form of the COUNT() function basically returns the number of rows in a result set returned by a SELECT statement.
Sum is doing the mathematical sum, whereas count simply counts any value as 1 regardless of what data type.
SELECT COUNT(count) FROM (SELECT COUNT(source) AS count
FROM call_details
GROUP BY source
HAVING count > 1) as A
You can't get a global total in a row-context. At the time the the COUNT() completes on any particular row, there's nothing to SUM, because the other rows haven't been calculated yet.
You'd have to run the SUM query first to get your individual stats, then sum manually in your script, or re-run the query with a surrounding SUM clause:
SELECT SUM(count) FROM (
SELECT original query here...
)
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