I am trying to prepare a subject wise merit list. I am using this mysql query
:
SELECT *
FROM results
ORDER BY qid ASC,
marks DESC
Result is:
But what I need is like this (look at marks column, I need to get same qid
rows, ordered by marks
):
Please anyone help me.
Update:
And this is result.sql
file to create the table in your pc.
-- phpMyAdmin SQL Dump
-- version 3.5.2.2
-- http://www.phpmyadmin.net
--
-- Host: 127.0.0.1
-- Generation Time: Mar 09, 2013 at 05:40 PM
-- Server version: 5.5.27
-- PHP Version: 5.4.7
SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO";
SET time_zone = "+00:00";
/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;
/*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */;
/*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */;
/*!40101 SET NAMES utf8 */;
--
-- Database: `ges_omeca`
--
-- --------------------------------------------------------
--
-- Table structure for table `results`
--
CREATE TABLE IF NOT EXISTS `results` (
`exam_id` int(11) NOT NULL AUTO_INCREMENT,
`sid` varchar(50) NOT NULL,
`qid` varchar(100) NOT NULL,
`corrects` int(3) NOT NULL,
`total_qs` int(3) NOT NULL,
`marks` float NOT NULL,
`date_time` datetime NOT NULL COMMENT 'DateTime when user submits the answer script.',
PRIMARY KEY (`exam_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=14 ;
--
-- Dumping data for table `results`
--
INSERT INTO `results` (`exam_id`, `sid`, `qid`, `corrects`, `total_qs`, `marks`, `date_time`) VALUES
(1, 'guest', 'EN_(Set-B)_(07.02.13)', 37, 40, 36.25, '2023-02-13 01:10:00'),
(2, 'guest', 'EN_(Set-B)_(07.02.13)', 11, 40, 10.25, '2013-02-23 01:56:58'),
(3, 'guest', 'P1_(Set-D)_(10.02.13)', 2, 100, 36.25, '2013-02-23 03:42:57'),
(4, 'guest', 'P1_(Set-B)_(09.02.13)', 5, 40, 5, '2013-02-23 03:46:59'),
(5, 'guest', 'EN_(Set-A)_(07.02.13)', 1, 40, 0.25, '2013-02-23 04:46:59'),
(6, 'guest', 'EN_(Set-A)_(07.02.13)', 6, 40, 5.5, '2013-02-23 04:59:59'),
(7, 'guest', 'P1_(Set-D)_(10.02.13)', 10, 100, 9.25, '2013-02-24 08:57:17'),
(8, 'guest', 'P1_(Set-B)_(09.02.13)', 5, 40, 5, '2013-02-24 01:23:50'),
(9, 'guest', 'EN_(Set-D)_(07.02.13)', 0, 40, -0.5, '2013-02-25 12:45:33'),
(10, 'guest', 'EN_(Set-D)_(07.02.13)', 2, 40, 1.5, '2013-02-25 01:45:38'),
(11, 'guest', 'P1_(Set-B)_(09.02.13)', 2, 40, 2, '2013-02-25 04:06:28'),
(12, 'guest', 'EN_(Set-C)_(07.02.13)', 5, 40, 4.5, '2013-02-25 04:42:27'),
(13, 'guest', 'P1_(Set-C)_(10.02.13)', 6, 40, 6, '2013-02-25 05:00:57');
/*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;
/*!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS */;
/*!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */;
The ORDER BY statement in SQL is used to sort the fetched data in either ascending or descending according to one or more columns. By default ORDER BY sorts the data in ascending order. We can use the keyword DESC to sort the data in descending order and the keyword ASC to sort in ascending order.
Discussion: If you want to select records from a table but would like to see them sorted according to two columns, you can do so with ORDER BY . This clause comes at the end of your SQL query.
To sort the records in descending order, use the DESC keyword. Syntax: SELECT * FROM table_name ORDER BY column_name; For Multiple column order, add the name of the column by which you'd like to sort records first.
Summary. Use the ORDER BY clause to sort the result set by one or more columns. Use the ASC option to sort the result set in ascending order and the DESC option to sort the result set in descending order. The ORDER BY clause is evaluated after the FROM and SELECT clauses.
This is exactly what you need:
SELECT *
FROM results
ORDER BY SUBSTRING( qid
FROM 1
FOR 1 ) ASC , marks DESC
I didn't really understand your question but looking on the result, I've noticed that records are sorted by qid
which contains EN
to be the first on the result list.
give this a try,
SELECT *
FROM tableName
ORDER BY CASE WHEN qid LIKE 'EN%' THEN 0
WHEN qid LIKE 'P1%' THEN 1
ELSE 2
END ASC,
marks DESC
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