I have followed a question here to use a Mysql query to dynamically convert rows to columns. This works fine, but i need to convert this on basis of two columns,
The query mentioned in above link works for a single column "data", but i want to work for two columns which are "data" and "price".
i have added an example here,
Given a table A, which look like
Table A
| id|order|data|item|Price|
-----+-----+----------------
| 1| 1| P| 1 | 50 |
| 1| 1| P| 2 | 60 |
| 1| 1| P| 3 | 70 |
| 1| 2| Q| 1 | 50 |
| 1| 2| Q| 2 | 60 |
| 1| 2| Q| 3 | 70 |
| 2| 1| P| 1 | 50 |
| 2| 1| P| 2 | 60 |
| 2| 1| P| 4 | 80 |
| 2| 3| S| 1 | 50 |
| 2| 3| S| 2 | 60 |
| 2| 3| S| 4 | 80 |
I like to write a query that looks like the following:
Result Table
| id|order1|order2|order3|item1|item2|item3|item4|
-----+-----+---------------------------------------
| 1| P | Q | | 50 | 60 | 70 | |
| 2| P | | S | 50 | 60 | | 80 |
I have tried to create two different queries and then a join to achieve this, but that may not be a good solution. Can any one suggest a solution same like mentioned in the link above.
Thanks
If you want to transpose only select row values as columns, you can add WHERE clause in your 1st select GROUP_CONCAT statement. If you want to filter rows in your final pivot table, you can add the WHERE clause in your SET statement.
A database table can store different types of data and sometimes we need to transform row-level data into column-level data. This problem can be solved by using the PIVOT() function. This function is used to rotate rows of a table into column values.
If you had a known number of values for both order
and item
, then you could hard code the query into:
select id,
max(case when `order` = 1 then data end) order1,
max(case when `order` = 2 then data end) order2,
max(case when `order` = 3 then data end) order3,
max(case when item = 1 then price end) item1,
max(case when item = 2 then price end) item2,
max(case when item = 3 then price end) item3,
max(case when item = 4 then price end) item4
from tableA
group by id;
See Demo. But part of the problem that you are going to have is because you are trying to transform multiple columns of data. My suggestion to get the final result would be to unpivot the data first. MySQL does not have an unpivot function but you can use a UNION ALL to convert the multiple pairs of columns into rows. The code to unpivot will be similar to the following:
select id, concat('order', `order`) col, data value
from tableA
union all
select id, concat('item', item) col, price value
from tableA;
See Demo. The result of this will be:
| ID | COL | VALUE |
-----------------------
| 1 | order1 | P |
| 1 | order1 | P |
| 1 | order1 | P |
| 1 | item1 | 50 |
| 1 | item2 | 60 |
| 1 | item3 | 70 |
As you can see this has taken the multiple columns of order
/data
and item
/price
and convert it into multiple rows. Once that is completed, then you can convert the values back into columns using an aggregate function with a CASE:
select id,
max(case when col = 'order1' then value end) order1,
max(case when col = 'order2' then value end) order2,
max(case when col = 'order3' then value end) order3,
max(case when col = 'item1' then value end) item1,
max(case when col = 'item2' then value end) item2,
max(case when col = 'item3' then value end) item3
from
(
select id, concat('order', `order`) col, data value
from tableA
union all
select id, concat('item', item) col, price value
from tableA
) d
group by id;
See Demo. Finally, you need to convert the above code into a dynamic prepared statement query:
SET @sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'max(case when col = ''',
col,
''' then value end) as `',
col, '`')
) INTO @sql
FROM
(
select concat('order', `order`) col
from tableA
union all
select concat('item', `item`) col
from tableA
)d;
SET @sql = CONCAT('SELECT id, ', @sql, '
from
(
select id, concat(''order'', `order`) col, data value
from tableA
union all
select id, concat(''item'', item) col, price value
from tableA
) d
group by id');
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
See SQL Fiddle with demo. This gives a result:
| ID | ORDER1 | ORDER2 | ORDER3 | ITEM1 | ITEM2 | ITEM3 | ITEM4 |
-------------------------------------------------------------------
| 1 | P | Q | (null) | 50 | 60 | 70 | (null) |
| 2 | P | (null) | S | 50 | 60 | (null) | 80 |
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