I have a string containing comma separated keywords. For Example:
$keywords = 'keyword1, keyword2, keyword3';
My Table schema, named tbl_address
is like this ( simplified ) :
id INT(11) PRIMARY KEY, AUTO INCREMENT
address VARCHAR(250) NOT NULL
Assume I have to use MySQLi
in PHP ( not PDO
).
Here is my current approach:
$result = array();
$keyword_tokens = explode(',', $keywords);
foreach($keyword_tokens as $keyword) {
$keyword = mysqli_real_escape_string(trim($keyword));
$sql = "SELECT * FROM tbl_address WHERE address LIKE'%$keyword%'";
// query and collect the result to $result
// before inserting to $result, check if the id exists in $result.
// if yes, skip.
}
return $result;
This approach works, but inefficient in performance. If there are a lot of keywords, it will make a lot queries.
My question is, is there a better way to achieve the same goal ? i.e. what is the simplest way to return all records with the address containing the ANY of the keywords ?
A simple REGEXP
might be what you're after. You'd have to check how efficient it is for yourself.
SELECT * FROM tbl_address WHERE field REGEXP 'keyword1|keyword2|keyword3';
SELECT * FROM user;
+---------+----------+
| user_id | username |
+---------+----------+
| 101 | Adam |
| 102 | Ben |
| 103 | Charlie |
| 104 | Dave |
+---------+----------+
SELECT *
FROM user
WHERE FIND_IN_SET(username,'adam,ben,dave') > 0;
+---------+----------+
| user_id | username |
+---------+----------+
| 101 | Adam |
| 102 | Ben |
| 104 | Dave |
+---------+----------+
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