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MySQL - PHP: Calculate total hours in a day between multiple events

I have this table named time_track:

+----+--------+---------------------+---------+
| id | emplid | ctimestamp          | eventid |
+----+--------+---------------------+---------+
| 1  | 13     | 2016-06-02 03:41:41 | 1       |
+----+--------+---------------------+---------+
| 2  | 13     | 2016-06-02 09:04:49 | 2       |
+----+--------+---------------------+---------+
| 3  | 13     | 2016-06-02 10:03:13 | 1       |
+----+--------+---------------------+---------+
| 4  | 13     | 2016-06-02 13:21:23 | 2       |
+----+--------+---------------------+---------+

where eventid 1 = Start work and eventid 2 = Stop work.

How can I calculate the hours of any given day taking into consideration that working hours are the total hours between all eventid's 1 and 2 - WHERE emplid = 13 AND Year(ctimestamp) = 2016 and Month(ctimestamp) = 06 and Day(ctimestamp) = 02

like image 639
jQuerybeast Avatar asked Jun 30 '16 15:06

jQuerybeast


1 Answers

You can also do it with PHP (instead of SQL) :

<?php
$data = array( array( "1","2016-06-02 03:41:41" ),
               array( "2","2016-06-02 09:04:49" ),
               array( "1","2016-06-02 10:03:13" ),
               array( "2","2016-06-02 13:21:23" )
             );
$hours = 0;
foreach ( $data as $row ) // PROCESS ALL ROWS FROM QUERY.
{ if ( $row[ 0 ] == "1" ) // IF CURRENT ROW IS START TIME
       $start = strtotime( $row[ 1 ] );
  else { $stop = strtotime( $row[ 1 ] ); // STOP TIME. CALCULATE.
         $hours += ( $stop - $start ) / 3600;
       }
}
echo $hours; // 8.6883333333333.
?>

You can round the result.

Copy-paste previous code in a file, save it as .PHP and open it in your browser. Feel free to change the sample data.

Edit : it's easier to call a function to calculate all the hours :

<?php

function total_hours ( $data )
{ $hours = 0;
  foreach ( $data as $row )
    if ( $row[ "eventid" ] == "1" )
         $start = strtotime( $row[ "ctimestamp" ] );
    else { $stop = strtotime( $row[ "ctimestamp" ] );
           $hours += ( $stop - $start ) / 3600;
         }
  return $hours;
}

$sample_data = array( array( "id"         => 1,
                             "emplid"     => 13,
                             "ctimestamp" => "2016-06-02 03:41:41",
                             "eventid"    => 1 ),
                      array( "id"         => 2,
                             "emplid"     => 13,
                             "ctimestamp" => "2016-06-02 09:04:49",
                             "eventid"    => 2 ),
                      array( "id"         => 3,
                             "emplid"     => 13,
                             "ctimestamp" => "2016-06-02 10:03:13",
                             "eventid"    => 1 ),
                      array( "id"         => 4,
                             "emplid"     => 13,
                             "ctimestamp" => "2016-06-02 13:21:23",
                             "eventid"    => 2 )
                    );
echo total_hours( $sample_data ); // 8.6883333333333.
?>

Call this function with the sql-result you get from the query as parameter (and replace the foreach by while ( $row = mysqli_fetch_array ).

like image 66
Jose Manuel Abarca Rodríguez Avatar answered Oct 11 '22 12:10

Jose Manuel Abarca Rodríguez