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mysql partitioning with unix_timestamp from variable

Given this :

delimiter //
create procedure setup()
begin
  declare d datetime;
  set d = rounddate(now());

  create table s_time (req_id int not null,
                       ser_id int not null,
                       hel_id int not null,
                       posted int unsigned not null,
                       completed int unsigned not null default 0
                      )
  partition by range (completed) (partition p0 values less than ( unix_timestamp(d) ),
                                  partition p1 values less than ( unix_timestamp(d + interval 1 day) )
                                 );
end//

I get :

ERROR 1064 (42000) : Constant, random, or timezone-dependent expression in (sub)partitioning function are not allowed

Is there any way to get this to work, or do I have to use a hard-coded string for the input. ie use : unix_timestamp('2012-07-07 00:00:00')

like image 768
Kassym Dorsel Avatar asked Jun 22 '12 19:06

Kassym Dorsel


1 Answers

To keep the solution in full sql this is what I have found.

delimiter //
create procedure setup()
begin
  declare d, d2 int;
  set d = unix_timestamp();
  set d2 = unix_timestamp(now() + interval 1 day);

  create table s_time (req_id int not null,
                       ser_id int not null,
                       hel_id int not null,
                       posted int unsigned not null,
                       completed int unsigned not null default 0
                      );

  SET @stmt = concat('alter table s_time PARTITION BY RANGE (completed) (
                      partition p0 values less than (', d, '),
                      partition p1 values less than (', d2, '))');
  PREPARE pStmt FROM @stmt;
  EXECUTE pStmt;
  DEALLOCATE PREPARE pStmt;

end//
delimiter ;
call setup();
like image 171
Kassym Dorsel Avatar answered Oct 27 '22 11:10

Kassym Dorsel