Currently I am doing a very basic OrderBy in my statement.
SELECT * FROM tablename WHERE visible=1 ORDER BY position ASC, id DESC
The problem with this is that NULL entries for 'position' are treated as 0. Therefore all entries with position as NULL appear before those with 1,2,3,4. eg:
NULL, NULL, NULL, 1, 2, 3, 4
Is there a way to achieve the following ordering:
1, 2, 3, 4, NULL, NULL, NULL.
If you sort a column with NULL values in ascending order, the NULLs will come first. Alternatively, if you add a DESC keyword to get a descending order, NULLs will appear last.
If you specify the ORDER BY clause, NULL values by default are ordered as less than values that are not NULL. Using the ASC order, a NULL value comes before any non-NULL value; using DESC order, the NULL comes last.
1 Answer. The correct answer is, option (a): Null values are displayed last in the ascending sequences.
If the null ordering is not specified then the handling of the null values is: - NULLS LAST if the sort is ASC - NULLS FIRST if the sort is DESC - If neither ascending nor descending order is specified, and the null ordering is also not specified, then both defaults are used and thus the order will be ascending with ...
MySQL has an undocumented syntax to sort nulls last. Place a minus sign (-) before the column name and switch the ASC to DESC:
SELECT * FROM tablename WHERE visible=1 ORDER BY -position DESC, id DESC
It is essentially the inverse of position DESC
placing the NULL values last but otherwise the same as position ASC
.
A good reference is here http://troels.arvin.dk/db/rdbms#select-order_by
I found this to be a good solution for the most part:
SELECT * FROM table ORDER BY ISNULL(field), field ASC;
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