I'm building a search within my site. I have a problem with the DB. It's giving me this:
Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\Program Files (x86)\EasyPHP-5.3.5.0\www\searchscript\search.php on line 86
I'll show you the code section where it gives me such error
line 82: $query = "SELECT * FROM dreams WHERE titolo,titch LIKE \"%$trimmed%\" ORDER BY id_dreams DESC ";
line 85: $numresults=mysql_query($query);
line 86: $numrows=mysql_num_rows($numresults); //error
Now I tried to see what is the problem behind the query and it's telling me this:
SELECT * FROM dreams WHERE titolo, titch LIKE "%tags%" ORDER BY id_dreams DESC
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'titch LIKE "%tags%" ORDER BY id_dreams DESC' at line 1
The code behind this is:
$query = "SELECT * FROM dreams WHERE titolo, titch LIKE \"%$trimmed%\" ORDER BY id_dreams DESC ";
$result = mysql_query($query) or die($query."<br/><br/>".mysql_error());
The mysql_query is returning a boolean value meaning the sql query is probably failing and you're getting a false returned rather than a mysql resource.
Have you checked your query?
You forgot to check whether $num_results
is a MySQL result resource. In this case your query errored, so it's FALSE
instead.
Re-read the documentation for mysql_query
and ensure you program for all possible cases.
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