I have two MySQL questions.
$query = " SELECT
stationname
FROM
stations
WHERE
stationname >= '". mysql_real_escape_string($_GET['letter']) ."'
ORDER BY
stationname
";
Here is the first query. In the URL is a parameter set $_GET['letter']
containing an Alphabetic character. I'm trying to select all the rows where stationname
starts with $_GET['letter']
. So i found this solution in an other Stackoverflow topic, but it doesn't seem to work, i get all my rows, and not just that single one. edit : seems it checks for all the characters in stationname
, and not just the starting letter, how can i get that?
$query = " SELECT
stationname
FROM
stations
WHERE
stationname
LIKE
'". mysql_real_escape_string($_POST['search']) ."'
";
Second and final question. I want to make a search engine for my website, selecting all the rows where stationname
contains $_POST['search']
. But when i have 2 rows, one for example called cheese
and the other one called cheese2
, and i search for cheese
, only cheese
get selected, and when i search for cheese2
, only cheese2
will get selected. Is there any way to select both cheese
and cheese2
?
LIKE
supports wildcards. %
means any number of characters (including zero), and _
means any one character`
stationname LIKE 'cheese%'
This would match cheese
and cheese2
.
You can use the %
for the first issue too.
stationname LIKE 'a%'
This will find all words that start with 'a'
.
I'm trying to select all the rows where stationname starts with $_GET['letter']
MySQL has a LEFT
function which seems to be what you're looking for. So basically we extract the first letter of the stationname
and compare it agains your letter:
where left(stationname, 1) = '" . mysql_real_escape_string($_GET['letter']) . "'";
Is there any way to select both cheese and cheese2?
Well here the solution is a little smelly, as you should check whether cheese
is contained in cheese2
and also whether cheese2
is contained in cheese
. Try this:
where stationname like '%" . mysql_real_escape_string($_POST['search']) .
"%' OR '" . mysql_real_escape_string($_POST['search']) .
"' like concat('%', stationname, '%')";
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