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MySQL: Get column name or alias from query

I'm not asking for the SHOW COLUMNS command.

I want to create an application that works similarly to heidisql, where you can specify an SQL query and when executed, returns a result set with rows and columns representing your query result. The column names in the result set should match your selected columns as defined in your SQL query.

In my Python program (using MySQLdb) my query returns only the row and column results, but not the column names. In the following example the column names would be ext, totalsize, and filecount. The SQL would eventually be external from the program.

The only way I can figure to make this work, is to write my own SQL parser logic to extract the selected column names.

Is there an easy way to get the column names for the provided SQL? Next I'll need to know how many columns does the query return?

# Python  import MySQLdb  #=================================================================== # connect to mysql #===================================================================  try:     db = MySQLdb.connect(host="myhost", user="myuser", passwd="mypass",db="mydb") except MySQLdb.Error, e:     print "Error %d: %s" % (e.args[0], e.args[1])     sys.exit (1)  #=================================================================== # query select from table #===================================================================  cursor = db.cursor ()     cursor.execute ("""\      select ext,         sum(size) as totalsize,         count(*) as filecount      from fileindex     group by ext     order by totalsize desc; """)  while (1):     row = cursor.fetchone ()     if row == None:         break     print "%s %s %s\n" % (row[0], row[1], row[2])  cursor.close() db.close()       
like image 863
panofish Avatar asked Feb 15 '11 22:02

panofish


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1 Answers

cursor.description will give you a tuple of tuples where [0] for each is the column header.

num_fields = len(cursor.description) field_names = [i[0] for i in cursor.description] 
like image 173
user625477 Avatar answered Oct 10 '22 17:10

user625477