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Mysql: execute command denied to user ''@'localhost' for routine error

i got some problem during open my old website. My dataTable show:

DataTables warning: JSON data from server could not be parsed. This is caused by a JSON formatting error.

After that, I tried to debug my script and found error in mysql:

Error occuered during query execution: 
(<small>SELECT SQL_CALC_FOUND_ROWS ID,name,remark,avrusepmonth 
        , CONCAT('&lt;input type=''checkbox''id=''cb' , ID ,''' name=''check[]''                
        value=''',ID,''' &gt;','&lt;label class=''lbcb'' for=''cb', 
        ID,'''&gt;&lt;=update=&lt;/label&gt;') as checkb 
        ,monthavrage(ID,12) as latestavr , moq, leadtime 
        FROM test_media  WHERE nowuse=1 and monthavrage(ID,12)  &gt; 0  ORDER BY  name
        desc, ID
        LIMIT 0, 10</small>):
 execute command denied to user 'jeinqa'@'localhost' for routine 'TestMediaControl.monthavrage'

Then I tried to googling for execute command denied to user 'jeinqa'@'localhost' for routine 'TestMediaControl.monthavrage' and some sites said that I must do some GRANT:

GRANT EXECUTE ON PROCEDURE TestMediaControl.monthavrage TO 'jeinqa'@'localhost'

but I got:

#1370 - execute command denied to user 'jeinqa'@'localhost' for routine 'TestMediaControl.monthavrage'

could you tell me how should I do for solving this?

like image 473
nunu Avatar asked Jun 22 '11 03:06

nunu


3 Answers

It works..... I try to grant this priviledge in root.

  1. log in as root
  2. GRANT EXECUTE ON PROCEDURE TestMediaControl.monthavrage TO 'jeinqa'@'localhost'
  3. flush privileges;
like image 76
nunu Avatar answered Nov 17 '22 12:11

nunu


Very late to the party also try a combination of.

GRANT EXECUTE ON PROCEDURE TestMediaControl.monthavrage TO 'jeinqa'@'%';

AND

flush privileges;

Also try replacing PROCEDURE with FUNCTION.

like image 22
Sydwell Avatar answered Nov 17 '22 12:11

Sydwell


I have encountered this in phpMyAdmin, a few hours ago, when executing a stored procedure with what I thought would be detected as a syntax error.

I was missing a comma between a field name, and a calculated field, and this gave me the same error message.

like image 8
Max Izrin Avatar answered Nov 17 '22 11:11

Max Izrin