I seem to be having trouble setting up a Foreign Key
between two of my tables.
Here is the CREATE
clause for each table:
CREATE TABLE IF NOT EXISTS `dbname`.`CallRecord` (
`id` INT NOT NULL AUTO_INCREMENT,
`user_id` INT NOT NULL,
`city_id` INT NOT NULL,
`created` DATETIME NULL,
`timestamp` TIMESTAMP NULL,
PRIMARY KEY (`id`),
INDEX `user_id_fk_idx` (`user_id` ASC),
INDEX `city_id_fk_idx` (`city_id` ASC),
CONSTRAINT `user_id_fk`
FOREIGN KEY (`user_id`)
REFERENCES `dbname`.`User` (`id`)
ON DELETE RESTRICT
ON UPDATE NO ACTION,
CONSTRAINT `city_id_fk`
FOREIGN KEY (`city_id`)
REFERENCES `dbname`.`City` (`id`)
ON DELETE RESTRICT
ON UPDATE NO ACTION)
ENGINE = InnoDB;
And here is the other table:
CREATE TABLE IF NOT EXISTS `dbname`.`DataCallAssoc` (
`id` INT NOT NULL AUTO_INCREMENT,
`data_id` INT NOT NULL,
`call_record_id` INT NOT NULL,
PRIMARY KEY (`id`),
INDEX `data_id_fk_idx` (`data_id` ASC),
INDEX `call_record_id_fk_idx` (`call_record_id` ASC),
CONSTRAINT `data_id_fk`
FOREIGN KEY (`data_id`)
REFERENCES `dbname`.`Data` (`id`)
ON DELETE CASCADE
ON UPDATE NO ACTION,
CONSTRAINT `call_record_id_fk`
FOREIGN KEY (`call_record_id`)
REFERENCES `dbname`.`CallRecord` (`id`)
ON DELETE CASCADE
ON UPDATE NO ACTION)
ENGINE = InnoDB;
The problem lies with the last CONSTRAINT
of DataCallAssoc
:
CONSTRAINT `call_record_id_fk`
FOREIGN KEY (`call_record_id`)
REFERENCES `dbname`.`CallRecord` (`id`)
ON DELETE CASCADE
ON UPDATE NO ACTION)
I am getting this error:
Error creating foreign key on call_record_id (check data types)
Even when I create the table and foreign keys separately. Every other foreign keys work, and even other tables that point to CallRecord.id
as a foreign key works.
I also checked that CallRecord.id
is the same as DataCallAssoc.call_record_id
in terms of structure.
As well as making sure the data-type is the same, for some types, such as bigint(20), if the primary-key is unsigned then the foreign-key must be unsigned as well. "unsigned" is one of the attributes of a field.
The Error Creating Foreign Key...(check data types) error ALSO occurs if you already have a foreign key of the same name in another table. So if you run into this most unhelpful error message, make sure your data types match and ALSO foreign key names are unique. Hope this helps someone.
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