First let me mention that I've gone through many suggested questions and found no relevent answer. Here is what I'm doing.
I'm connected to my Amazon EC2 instance. I can login with MySQL root with this command:
mysql -u root -p
Then I created a new user bill with host %
CREATE USER 'bill'@'%' IDENTIFIED BY 'passpass';
Granted all the privileges to user bill:
grant all privileges on *.* to 'bill'@'%' with grant option;
Then I exit from root user and try to login with bill:
mysql -u bill -p
entered the correct password and got this error:
ERROR 1045 (28000): Access denied for user 'bill'@'localhost' (using password: YES)
Use the ALTER USER command and change the authentication method to log into MySQL as root: ALTER USER 'root'@'localhost' IDENTIFIED WITH mysql_native_password BY 'insert_password'; This command changes the password for the user root and sets the authentication method to mysql_native_password.
To resolve the error, you must create a user with the following command: mysql> GRANT ALL ON *. * to user_name@localhost IDENTIFIED BY 'password'; Replace user_name with the user's username and password with the user's password.
You probably have an anonymous user ''@'localhost'
or ''@'127.0.0.1'
.
As per the manual:
When multiple matches are possible, the server must determine which of them to use. It resolves this issue as follows: (...)
- When a client attempts to connect, the server looks through the rows [of table mysql.user] in sorted order.
- The server uses the first row that matches the client host name and user name.
(...) The server uses sorting rules that order rows with the most-specific Host values first. Literal host names [such as 'localhost'] and IP addresses are the most specific.
Hence, such an anonymous user would "mask" any other user like '[any_username]'@'%'
when connecting from localhost
.
'bill'@'localhost'
does match 'bill'@'%'
, but would match (e.g.) ''@'localhost'
beforehands.
The recommended solution is to drop this anonymous user (this is usually a good thing to do anyways).
Below edits are mostly irrelevant to the main question. These are only meant to answer some questions raised in other comments within this thread.
Edit 1
Authenticating as 'bill'@'%'
through a socket.
root@myhost:/home/mysql-5.5.16-linux2.6-x86_64# ./mysql -ubill -ppass --socket=/tmp/mysql-5.5.sock Welcome to the MySQL monitor (...) mysql> SELECT user, host FROM mysql.user; +------+-----------+ | user | host | +------+-----------+ | bill | % | | root | 127.0.0.1 | | root | ::1 | | root | localhost | +------+-----------+ 4 rows in set (0.00 sec) mysql> SELECT USER(), CURRENT_USER(); +----------------+----------------+ | USER() | CURRENT_USER() | +----------------+----------------+ | bill@localhost | bill@% | +----------------+----------------+ 1 row in set (0.02 sec) mysql> SHOW VARIABLES LIKE 'skip_networking'; +-----------------+-------+ | Variable_name | Value | +-----------------+-------+ | skip_networking | ON | +-----------------+-------+ 1 row in set (0.00 sec)
Edit 2
Exact same setup, except I re-activated networking, and I now create an anonymous user ''@'localhost'
.
root@myhost:/home/mysql-5.5.16-linux2.6-x86_64# ./mysql Welcome to the MySQL monitor (...) mysql> CREATE USER ''@'localhost' IDENTIFIED BY 'anotherpass'; Query OK, 0 rows affected (0.00 sec) mysql> Bye root@myhost:/home/mysql-5.5.16-linux2.6-x86_64# ./mysql -ubill -ppass \ --socket=/tmp/mysql-5.5.sock ERROR 1045 (28000): Access denied for user 'bill'@'localhost' (using password: YES) root@myhost:/home/mysql-5.5.16-linux2.6-x86_64# ./mysql -ubill -ppass \ -h127.0.0.1 --protocol=TCP ERROR 1045 (28000): Access denied for user 'bill'@'localhost' (using password: YES) root@myhost:/home/mysql-5.5.16-linux2.6-x86_64# ./mysql -ubill -ppass \ -hlocalhost --protocol=TCP ERROR 1045 (28000): Access denied for user 'bill'@'localhost' (using password: YES)
Edit 3
Same situation as in edit 2, now providing the anonymous user's password.
root@myhost:/home/mysql-5.5.16-linux2.6-x86_64# ./mysql -ubill -panotherpass -hlocalhost Welcome to the MySQL monitor (...) mysql> SELECT USER(), CURRENT_USER(); +----------------+----------------+ | USER() | CURRENT_USER() | +----------------+----------------+ | bill@localhost | @localhost | +----------------+----------------+ 1 row in set (0.01 sec)
Conclusion 1, from edit 1: One can authenticate as 'bill'@'%'
through a socket.
Conclusion 2, from edit 2: Whether one connects through TCP or through a socket has no impact on the authentication process (except one cannot connect as anyone else but 'something'@'localhost'
through a socket, obviously).
Conclusion 3, from edit 3: Although I specified -ubill
, I have been granted access as an anonymous user. This is because of the "sorting rules" advised above. Notice that in most default installations, a no-password, anonymous user exists (and should be secured/removed).
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