I would like to multiply several columns in my data frame by a vector of values. The specific vector of values changes depending on the value in another column.
--EDIT--
What if I make the data set more complicated, i.e., more than 2 conditions and the conditions are randomly shuffled around the data set?
Here is an example of my data set:
df=data.frame(
Treatment=(rep(LETTERS[1:4],each=2)),
Species=rep(1:4,each=2),
Value1=c(0,0,1,3,4,2,0,0),
Value2=c(0,0,3,4,2,1,4,5),
Value3=c(0,2,4,5,2,1,4,5),
Condition=c("A","B","A","C","B","A","B","C")
)
Which looks like:
Treatment Species Value1 Value2 Value3 Condition
A 1 0 0 0 A
A 1 0 0 2 B
B 2 1 3 4 A
B 2 3 4 5 C
C 3 4 2 2 B
C 3 2 1 1 A
D 4 0 4 4 B
D 4 0 5 5 C
If Condition=="A"
, I would like to multiply columns 3-5 by the vector c(1,2,3)
. If Condition=="B"
, I would like to multiply columns 3-5 by the vector c(4,5,6)
. If Condition=="C"
, I would like to multiply columns 3-5 by the vector c(0,1,0)
. The resulting data frame would therefore look like this:
Treatment Species Value1 Value2 Value3 Condition
A 1 0 0 0 A
A 1 0 0 12 B
B 2 1 6 12 A
B 2 0 4 0 C
C 3 16 10 12 B
C 3 2 2 3 A
D 4 0 20 24 B
D 4 0 5 0 C
I have tried subsetting the data frame and multiplying by the vector:
t(t(subset(df[,3:5],df[,6]=="A")) * c(1,2,3))
But I can't return the subsetted data frame to the original. Is there any way to perform this operation without subsetting the data frame, so that other columns (e.g., Treatment, Species) are preserved?
Here's a fairly general solution that you should be able to adapt to fit your needs.
Note the first argument in the outer
call is a logical vector and the second is numeric, so before multiplication TRUE
and FALSE
are converted to 1
and 0
, respectively. We can add the outer
results because the conditions are non-overlapping and the FALSE
elements will be zero.
multiples <-
outer(df$Condition=="A",c(1,2,3)) +
outer(df$Condition=="B",c(4,5,6)) +
outer(df$Condition=="C",c(0,1,0))
df[,3:5] <- df[,3:5] * multiples
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