Multiplication of two integers using bitwise operators

Question

How can I multipy two integers using bitwise operators?

I found an implementation here. Is there a better way of implementing multiplication?

For example: 2 * 6 = 12 must be performed using bitwise operators.

NOTE: Numbers are arbitrary, not power of 2

Answer 1

#include <stdio.h>  int main(void) {     int a, b, result;     printf("Enter the numbers to be multiplied:");     scanf("%d%d", &a, &b);       // a > b     result = 0;     while (b != 0)               // Iterate the loop till b == 0     {         if (b & 1)               // Bitwise & of the value of b with 1         {             result = result + a;  // Add a to result if b is odd .         }         a <<= 1;                    // Left shifting the value contained in 'a' by 1                                   // Multiplies a by 2 for each loop         b >>= 1;                    // Right shifting the value contained in 'b' by 1.     }      printf("Result: %d\n",result); } 

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