My platform is windows vista 32, with visual c++ express 2008 .
for example:
if i have a file contains 4000 bytes, can i have 4 threads read from the file at same time? and each thread access a different section of the file.
thread 1 read 0-999, thread 2 read 1000 - 2999, etc.
please give a example in C language.
In order to read the file, only one thread is enough. You won't gain anything by reading from several threads.
Multiple threads accessing shared data simultaneously may lead to a timing dependent error known as data race condition. Data races may be hidden in the code without interfering or harming the program execution until the moment when threads are scheduled in a scenario (the condition) that break the program execution.
When two threads access the same resources, weird things happen. To avoid that, always lock the resource. Python has the convenient threading. Lock for that, as well as some other tools (see documentation of the threading module).
While fread() and fwrite() are thread safe, the stream buffer represented by the FILE* is not. So you can have multiple threads accessing the same file, but not via the same FILE* - each thread must have its own, and the file to which they refer must be shareable - which is OS dependent.
If you don't write to them, no need to take care of sync / race condition.
Just open the file with shared reading as different handles and everything would work. (i.e., you must open the file in the thread's context instead of sharing same file handle).
#include <stdio.h>
#include <windows.h>
DWORD WINAPI mythread(LPVOID param)
{
int i = (int) param;
BYTE buf[1000];
DWORD numread;
HANDLE h = CreateFile("c:\\test.txt", GENERIC_READ, FILE_SHARE_READ,
NULL, OPEN_EXISTING, 0, NULL);
SetFilePointer(h, i * 1000, NULL, FILE_BEGIN);
ReadFile(h, buf, sizeof(buf), &numread, NULL);
printf("buf[%d]: %02X %02X %02X\n", i+1, buf[0], buf[1], buf[2]);
return 0;
}
int main()
{
int i;
HANDLE h[4];
for (i = 0; i < 4; i++)
h[i] = CreateThread(NULL, 0, mythread, (LPVOID)i, 0, NULL);
// for (i = 0; i < 4; i++) WaitForSingleObject(h[i], INFINITE);
WaitForMultipleObjects(4, h, TRUE, INFINITE);
return 0;
}
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