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I'm new to c++ and I came across below code snippet which looks strange for me.
const char* keys = "hello" "world";
std::cout << keys << std::endl;
Above code prints helloworld in the console. Is it syntactically valid to assign two string literals to a const char* in the same statement? if so, how it will be stored in memory?
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Variables defined with const cannot be Redeclared. Variables defined with const cannot be Reassigned. Variables defined with const have Block Scope.
In C++, string literals are stored in arrays of const char , so that any attempt to modify the literal's contents will trigger a diagnostic at compile time. As Christian points out, the const keyword was not originally a part of C.
string is an object meant to hold textual data (a string), and char* is a pointer to a block of memory that is meant to hold textual data (a string). A string "knows" its length, but a char* is just a pointer (to an array of characters) -- it has no length information.
The string str can be written in multiple lines by using two double quotes ( “ “ ) to break the string at any point in the middle. Then the string is displayed using puts. The code snippet that shows this is as follows.
It's a rule of C++ (and C) adjacent string literals are concatenated prior to compilation (but after macro expansion IIRC).
This happens anywhere, not just as part of an assignment statement.
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