One of the most powerful parts of Django is the automatic admin interface. It reads metadata from your models to provide a quick, model-centric interface where trusted users can manage content on your site. The admin's recommended use is limited to an organization's internal management tool.
The Django framework comes with a powerful administrative tool called admin. You can use it out of the box to quickly add, delete, or edit any database model from a web interface. But with a little extra code, you can customize the Django admin to take your admin capabilities to the next level.
Django admin allows access to users marked as is_staff=True . To disable a user from being able to access the admin, you should set is_staff=False . This holds true even if the user is a superuser. is_superuser=True .
I've found one way to achieve what I want, by using proxy models to get around the fact that each model may be registered only once.
class PostAdmin(admin.ModelAdmin):
list_display = ('title', 'pubdate','user')
class MyPost(Post):
class Meta:
proxy = True
class MyPostAdmin(PostAdmin):
def get_queryset(self, request):
return self.model.objects.filter(user = request.user)
admin.site.register(Post, PostAdmin)
admin.site.register(MyPost, MyPostAdmin)
Then the default PostAdmin
would be accessible at /admin/myapp/post
and the list of posts owned by the user would be at /admin/myapp/myposts
.
After looking at http://code.djangoproject.com/wiki/DynamicModels, I've come up with the following function utility function to do the same thing:
def create_modeladmin(modeladmin, model, name = None):
class Meta:
proxy = True
app_label = model._meta.app_label
attrs = {'__module__': '', 'Meta': Meta}
newmodel = type(name, (model,), attrs)
admin.site.register(newmodel, modeladmin)
return modeladmin
This can be used as follows:
class MyPostAdmin(PostAdmin):
def get_queryset(self, request):
return self.model.objects.filter(user = request.user)
create_modeladmin(MyPostAdmin, name='my-posts', model=Post)
Paul Stone answer is absolutely great! Just to add, for Django 1.4.5 I needed to inherit my custom class from admin.ModelAdmin
class MyPostAdmin(admin.ModelAdmin):
def queryset(self, request):
return self.model.objects.filter(id=1)
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