I am sending a file over POST together with text "name" using this form:
<form enctype="multipart/form-data" action="https://site[DOT]net/upload" method="post">
<input id="name" type="text" />
<input id="data" type="file" />
<button type="submit" name="submit" />
</form>
I would like to do the exect same using javascript. In addition I dont want to be redirected. I want to stay on the html page and just show a popup "Upload done". How can I do this in javascript (no jquery)?
EDIT:
I tried this code but the POST is not working:
<script>
function uploader {
var formData = new FormData();
formData.append("name", "Smith");
formData.append("data", fileInputElement.files[0]);
var request = new XMLHttpRequest();
request.open("POST", "https://site[DOT]net/upload");
request.send(formData);
}
</script>
<form>
<input id="name" type="text" />
<input id="data" type="file" />
<button type="submit" name="submit" />
<button onclick="uploader()">Click</button>
</form>
In case any wants to do this with the new fetch instead of xhr this is the equivalent. Also see: How do I POST with multipart form data using fetch?
var form = document.getElementById('formid');
form.onsubmit = async (e) => {
e.preventDefault();
const form = e.currentTarget;
const url = form.action;
try {
const formData = new FormData(form);
const response = await fetch(url, {
method: 'POST',
body: formData
});
console.log(response);
} catch (error) {
console.error(error);
}
}
<form id="formid" enctype="multipart/form-data" action="#" method="post">
<input id="name" type="text" />
<input id="data" type="file" />
<button type="submit" name="submit">Submint</button>
</form>
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