I am trying to do something very similar to a question I have asked before but I cant seem to get it to work correctly. Here is my previous question: How to get totals per day
the table looks as follows:
Table Name: Totals
Date |Program label |count
| |
2013-04-09 |Salary Day |4364
2013-04-09 |Monthly |6231
2013-04-09 |Policy |3523
2013-04-09 |Worst Record |1423
2013-04-10 |Salary Day |9872
2013-04-10 |Monthly |6543
2013-04-10 |Policy |5324
2013-04-10 |Worst Record |5432
2013-04-10 |Salary Day |1245
2013-04-10 |Monthly |6345
2013-04-10 |Policy |5431
2013-04-10 |Worst Record |5232
My question is: Using MSSQL 2008 - Is there a way for me to get the total counts per Program Label per day for the current month. As you can see sometimes it will run twice a day. I need to be able to account for this.
The output should look as follows:
Date |Salary Day |Monthly |Policy |Worst Record
2013-04-9 |23456 |63241 |23521 |23524
2013-04-10|45321 |72535 |12435 |83612
Use the PIVOT
table operator like this:
SELECT *
FROM Totals AS t
PIVOT
(
SUM(count)
FOR [Program label] IN ([Salary Day],
[Monthly],
[Policy],
[Worst Record])
) AS p;
See it in action:
This will give you:
| DATE | SALARY DAY | MONTHLY | POLICY | WORST RECORD |
-------------------------------------------------------------
| 2013-04-09 | 4364 | 6231 | 3523 | 1423 |
| 2013-04-10 | 11117 | 12888 | 10755 | 10664 |
Try this
select Date,
sum(case when [Program label] = 'Salary Day' then count else 0 end) [Salary Day],
sum(case when [Program label] = 'Monthly' then count else 0 end) [Monthly],
sum(case when [Program label] = 'Policy' then count else 0 end) [Policy],
sum(case when [Program label] = 'Worst Record' then count else 0 end) [Worst Record]
from Totals Group by [Date];
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