C++11 allows in-class initialization:
struct Foo{
std::vector<std::string> v{3}; // vector of 3 empty strings
};
If we wanted to initialize in-class a vector of ints, we would get something else:
struct Foo{
std::vector<int> v{3}; // vector of one element with value 3
};
This issue seems to be a limitation of the language, as discussed in previous questions. However, if this were not an in-class initialization, we would be able to use parentheses instead of braces, and get the desired result:
std::vector<int> v(3); // vector of three zeros
However, we cannot do this in a class because of most vexing parse:
struct Foo{
std::vector<int> v(3); // most vexing parse; doesn't compile
};
Of course, it's debatable whether the code above is good design practice, since we can easily just move what we're trying to do into a constructor. But temporarily putting that aside, is there a way to perform the desired initialization, as closely as possible to the first std::string
example, which works with no problem?
Default member initializers work with =
as well. So
struct Foo{
std::vector<int> v = std::vector<int>(3);
};
Will do it. Though obviously, a major caveat is the fact that we are repeating the type name here.
We can alleviate it somewhat with decltype
:
struct Foo{
std::vector<int> v = decltype(v)(3);
};
But that still has us naming things twice.
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